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inna [77]
3 years ago
9

∆IAM ~ ∆NOT. In ∆IAM, ∡A = 37° and in ∆NOT, ∡N = 43°. Find the measure of ∡O.

Mathematics
1 answer:
Kruka [31]3 years ago
4 0

Answer:

37°.

Step-by-step explanation:

It is given that \triangle IAM \sim \triangle NOT.

\angle A=37^\circ

\angle N=43^\circ

If two triangles are similar, then the measures of their corresponding angles are congruent.

\angle O\cong \angle A

m\angle O=m\angle A

m\angle O=37^\circ

Therefore, the measure of ∡O is 37°.

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Write two ratios equivalent to 24 : 9.
notsponge [240]

Answer:

8:3

16:6

Step-by-step explanation:

First, let's check if 9 and 24 have any common factor. If they do have any common ones, we must find the GCF (greatest common factor).

Factors of 9: 1, 3, 9

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

The common factors both of the numbers share and 1 and 3. To find the GCF, simply compare one of the factors to the other.

1 < 3

Now that we know the GCF, we can divide the two numbers in the ratio 24 : 9 by it (3).

24:9

24/3:9/3

<u>8:3</u>

Now that our ratio is simplified, it's going to be much easier to find more ratios that are equivalent. <u>8:3</u> is already one equivalent ratio, but if we multiply each number in the ratio by any other number, we can get a new equivalent ratio. Let's multiply each number in the ratio by 2:

<u>8:3</u>

8 ⋅ 2:3 ⋅ 2

<u>16:6</u>

<u></u>

So, another equivalent ratio to 24:9 (and <u>8:3</u>) is <u>16:6</u>.

3 0
2 years ago
Suppose that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The
Marina86 [1]

Answer:

Step-by-step explanation:

Given that you have eight cards. Five are green and three are yellow. The five green cards are numbered 1, 2, 3, 4, and 5. The three yellow cards are numbered 1, 2, and 3. The cards are well shuffled. You randomly draw one card.

G = card drawn is green

Y = card drawn is yellow

E = card drawn is even-numbered

List:

Sample space = {G1, G2, G3, G4, G5, Y1, Y2, Y3}

2) P(G) = 5/8

3) P(G/E) = P(GE)/P(E)

GE = {G2, G4}

Hence P(G/E) = 2/5

4) GE = {G2, G4}

P(GE) = 2/8 = 1/4

5) P(G or E) = P(G)+P(E)-P(GE)

= 5/8 + 3/8-2/8 = 3/5

6) No there is common element as G2 and G4

Cannot be mutually exclusive

6 0
3 years ago
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