S=<span>√(30df)
S= speed
d= length
f= friction
_______________________
S= ?
d= 74ft
f= 0.5
Witness says car was traveling +45mph
Plug in
</span>√(30[74][0.5])
subtract the result from 45
<span>
</span>
<h3>
<u>Given</u><u>:</u><u>-</u></h3>
- The hypotenuse of a right angle triangle is 13cm.
- One other side of the triangle is 1cm shorter than the hypotenuse.
<h3>
<u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u><u>-</u></h3>
Find the third scale of the triangle .
<h3>
<u>Solution:-</u><u> </u></h3>
Let the third Side be x.
According to the question,
★ Hypotenuse = 13 cm
★ Other side = Hypotenuse - 1 [ Given ]
= 13 cm - 1 cm
= 12 cm
Now,
<u>By pythagoras theorem</u>,
13² = 12² + x²
⇒ 169 = 144 + x²
⇒ x² = 169 - 144
⇒ x² = 25
⇒ x = √25
⇒ x = 5 cm
Hence, the third scale of the triangle is 5 cm.
Answer:
V = 196 mm³
Step-by-step explanation:
( 7/21 )³ = V / 5292
343 / 9261 = V / 5292
9261 V = 343 * 5292
V = 196 mm³
Could you explain please?
We are given the following two points.
Let us find the distance between these two points.
Recall that the distance formula is given by
