Answer:
it looses 200 in value for the first year
Step-by-step explanation:
I am in middle school first year.I have no idea how to solve this but i hope it helps
Answer:

Step-by-step explanation:
Given expression is
.
Now we need to find the cube root of given expression
.
![\sqrt[3]{27a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D)
![=\sqrt[3]{3*3*3a^{4*3}}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%2A3%2A3a%5E%7B4%2A3%7D%7D)
![=\sqrt[3]{3^3\left(a^4\right)^3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%5E3%5Cleft%28a%5E4%5Cright%29%5E3%7D)
![=\sqrt[3]{\left(3a^4\right)^3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B%5Cleft%283a%5E4%5Cright%29%5E3%7D)
Since cube root and cube are opposite operations of each other. So they will cancel each other.

Hence correct choice is the last choice
.
Check the picture below.
notice the tickmarks, thus TP = PU and TQ = QS, so the PQ segment is then a midsegment of the larger triangle, and thus the angles it makes on the small one, are exactly the same.
Answer:
B . 
Step-by-step explanation:
<u>Arithmetic sequence</u>:-
Step1:
Given sequence is 
Above sequence taking numerator terms
3,6,9,12,15 are in arithmetic progression
First term a= 3 and difference d = 3
now n t h term of given sequence is

now substitute a =3 and d=3

Step2:-
Above sequence taking denominator
4,5,6,7,8...
here a=4 and d=1



Final answer is the general term of given sequence is

Just write it out and make the sides equal to 37 like shown here. Have a great day/night!!