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2 years ago

If the surface area of a cube is 150 cm2, what is the volume of the cube

Mathematics

1 answer:

Fiesta28 [93]2 years ago

6 0

Answer:

V = 125 in^3

Step-by-step explanation:

A cube has 6 sides, and the area of each is equal to the side length squared:

A = 6x^2

A is given as 150 cm^2, and so is equal to 6x^2. Thus, x = the side length = 5 cm.

The volume of the same cube is given by V = x^3, which here is 5^3 in^3, or V = 125 in^3

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Mr. Gordon has 13 girls and 14 boys in his fourth period algebra class. One person is chosen at random.

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Answer:

Step-by-step explanation:

It's E because you have to add 13 and 14 and as you can see there's 14 boys so it's E.

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3 years ago

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3 years ago

Allison measured a line to be 5.4 inches long. If the actual length of the line is 5.5 inches, then what was the percent error o

valentina_108 [34]

Answer:

1.85%

Step-by-step explanation:

→ Find the difference between the actual and predicted

5.5 - 5.4 = 0.1

→ Divide answer by 5.4

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7 0

2 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

HURRY PLZ WILL GIVE BRAINLIEST AND 50 POINTS What is the value of x in the equation 4 5+ਬ-* 2 - (4-5 - 7

Inessa05 [86]

Answer:

6 I think

Step-by-step explanation:

7 + 5(x - 3) = 22

7 + 5x - 15 = 22

7 + 5x = 37

5x = 30

x = 6

{ 6 }

3 0

3 years ago