Answer:
b = (-3)/2
Step-by-step explanation:
Solve for b:
(-10 b)/3 = 5
Multiply both sides of (-10 b)/3 = 5 by -3/10:
(-3 (-10) b)/(10×3) = (-3)/10×5
(-3)/10×(-10)/3 = (-3 (-10))/(10×3):
(-3 (-10))/(10×3) b = (-3)/10×5
(-3)/10×5 = (-3×5)/10:
(-3 (-10) b)/(10×3) = (-3×5)/10
(-10)/10 = (10 (-1))/10 = -1:
(-3-1 b)/3 = (-3×5)/10
(-3)/3 = (3 (-1))/3 = -1:
--1 b = (-3×5)/10
(-1)^2 = 1:
b = (-3×5)/10
5/10 = 5/(5×2) = 1/2:
Answer: b = (-3)/2
Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:
In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:
If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
Answer:
The width of the rectangular lid is 15 cm.
Step-by-step explanation:1. Let's review the information given to us to answer the question correctly:
Length of the ribbon used by Jun = 56 cmLength of the rectangular lid = 13 cm
2. What is the width of the lid? The ribbon used by Jun is equivalent to the perimeter of the rectangular lid, therefore:Perimeter = 2 * Length + 2 * WidthReplacing with the values we have:56 = 2 * 13 + 2 * Width56 = 26 + 2Width2Width = 56 - 262Width = 30Width = 30/2Width = 15
Answer:
2 hrs 13 mins
Step-by-step explanation:
If Richard can paint the living room in 4 hrs, then in 1 hour he can paint 1/4 of the living .
If Vanessa can paint the living room in 5 hours, then in one hour, she can paint 1/5 of the living room.
In one hour Richard and Vanessa can paint 1/4 + 1/5 = 1/y
y is the number of hours it will take both Richard and Vanessa to paint the living room. 1/y is how much of the house they can paint in one hour.
1/4 + 1/5 = 1/y
(5 + 4)/20. ( find the LCM)
9/20 = 1/y
9y= 20
y = 20/9
y = 2.22hrs
y = 2 hrs 13 mins
