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Brilliant_brown [7]
3 years ago
6

Middle School teaches 6th, 7th, and 8th grade classes. The sixth grade has 318 students, the 7th has 286 students, and the 8th h

as 306 students. If the sixth grade takes a field trip and each student needs $3.50, how much total money is needed by the students? $910 c. $1113 b. $3185 d. $1071​
Mathematics
1 answer:
Ierofanga [76]3 years ago
8 0

Answer:

$3185

Step-by-step explanation:

Multiply the number of grade 6 students by the money needed ($3.50) and you get 318x3.50=1113

Multiply the number of grade 7 students by the money needed ($3.50) and you get  286x3.50=1001

Multiply the number of grade 8 students by the money needed ($3.50) and you get 306x3.50=1071

Add all the total amounts together and you get $3185

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The sum of two numbers is 12 The sum of the squares of the two numbers is 80. What are the two numbers?
defon

Answer:

4 and 8

Step-by-step explanation:

The square of 4 is 16 and the square of 8 is 64.

16 + 64 = 80

4 0
3 years ago
Tamara says she used the GCF to factor the expression 21x + 56xy as 7(3x + 8xy). Is she correct? Explain.
coldgirl [10]

Answer:

Tamara incorrectly factored the whole expression.

Step-by-step explanation:

Note that

•21x=3·7·x;

•56xy=2·2·2·7·x·y.

Mark in bold all common factors, then GCF(21x,56xy)=7·x=7x.

Thus,

21x+56xy=7x(3+8y).

Hence, Tamara correctly found the GCF of numbers 21 and 56, but incorrectly factored the whole expression.

6 0
3 years ago
Jamie Nolan purchased new cabinets for $12,640: laminate flooring for $4,560; countertops for
Goryan [66]

Answer:

total : 12371747

down payment : 10,515,984.95

Step-by-step explanation:

3 0
2 years ago
There are 200 9th graders in the freshman class. 2/5 of the students are girls. How
alekssr [168]

Answer: 80

Step-by-step explanation:

7 0
2 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
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