Answer:
c) Always results in a change in the protein for which the gene codes
Answer:
2.447 × 10⁴ years
Explanation:
Step 1: Given data
- Half-life of the radioactive atom (t1/2): 3,500 years
- Parent-daughter ratio ([A]/[A]₀): 1:127 (1/127)
Step 2: Calculate the rate constant
Radioactive decay follows first-order kinetics. We can calculate the rate constant (k) using the following equation.
k = ln2 / (t1/2) = ln2 / 3,500 y = 1.980 × 10⁻⁴ y⁻¹
Step 3: Calculate the time elapsed (t)
For first-order kinetics, we will use the following expression.
ln ([A]/[A]₀) = -k × t
t = ln ([A]/[A]₀)/ (-k)
t = ln (1/127) / (1.980 × 10⁻⁴ y⁻¹) = 2.447 × 10⁴ y
Answer:
2. tRNAQ binds the A site of the ribosome.
1. The polypeptide is transferred to tRNAQ.
4. The ribosome shifts, with tRNAQ still bound.
3. tRNAQ binds the P site of the ribosome.
4. The ribosome shifts, with tRNAQ still bound.
5. tRNAQ binds the E site of the ribosome.
Explanation:
tRNAQ first lands on the A site of the ribosome. It carries an amino acid according to the exposed codon on A site. A bond is formed between the amino acid of A and P site such that the polypeptide is transferred to tRNAQ. The ribosome shifts now and tRNA Q moves to P site from A site while still bound to mRNA. Another tRNA enters the A site and the above process is repeated which finally transfers the polypeptide chain from tRNAQ to new tRNA. tRNAQ has no attached polypeptide now and is ready to leave the translation complex. The ribosome shifts again with the tRNAQ still bound to mRNA. tRNAQ enters the E site from P site and finally leaves the translation complex by exiting the E site.
Answer:
Photosynthesis makes the glucose that is used in cellular respiration to make ATP. The glucose is then turned back into carbon dioxide, which is used in photosynthesis. While water is broken down to form oxygen during photosynthesis, in cellular respiration oxygen is combined with hydrogen to form water.
