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3 years ago

HURRYYY

Mathematics

1 answer:

puteri [66]3 years ago

4 0

Answer:

width=20m,length=23m

Step-by-step explanation:

as shown in the figure which is attached

let width of pool =x

⇒ length of pool=x+3

width of walk =2

⇒width of outer boundary of walk=x+4 (2 on each side of pool)

length of outer boundary of walk=x+3+4=x+7

area of pool =x×(x+3)

area of walk+pool=(x+4)×(x+7)

given

total area of the pool and walk is 188 square meters more than the area of the pool

⇒(x+4)×(x+7)=188+x×(x+3)

⇒8x=160

x=20m

dimensions of pool

widh=20m

length=20+3=23m

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