Answer:
width=20m,length=23m
Step-by-step explanation:
as shown in the figure which is attached
let width of pool =x
⇒ length of pool=x+3
width of walk =2
⇒width of outer boundary of walk=x+4 (2 on each side of pool)
length of outer boundary of walk=x+3+4=x+7
area of pool =x×(x+3)
area of walk+pool=(x+4)×(x+7)
given
total area of the pool and walk is 188 square meters more than the area of the pool
⇒(x+4)×(x+7)=188+x×(x+3)
⇒8x=160
x=20m
dimensions of pool
widh=20m
length=20+3=23m
Answer:
Step-by-step explanation:
Let the numbers be x and y
<h3>Given condition:</h3>x + y = 48 --------(1)
y = 7x -------------(2)
Put Eq. (2) in (1)
x + 7x = 48
8x = 48
Divide 8 to both sides
x = 48/8
<h3>x = 6</h3>Put x = 6 in Eq. (2)
y = 7 (6)
<h3>y = 42</h3>We are given sides of the triangle by expression
First side : n
Second side : m = 5n-5.
Third side : l = 5/4 m - n.
Perimeter is 90.
Therefore, first equation could be set :
n +m +l = 90 --------------equation(1)
Second equation would be
m = 5n-5 --------------equation(2)
Third equation would be
l = 5/4 m - n --------------equation(3)
Let us solve the system of equations by substitution.
Substituting m = 5n-5 and l = 5/4 m - n in first equation.
We get
n +5n-5 +5/4 m - n= 90
Now, substituting m = 5n-5 in above equation we get
n +5n-5 +5/4 (5n-5) - n= 90
5n + 25n/4 -5 - 25/4 =90
5n + 6.25n -5-6.25 = 90.
11.25n-11.25 = 90
Adding 11.25 on both sides, we get
11.25n-11.25+11.25 = 90+11.25
11.25n = 101.25.
Dividing both sides by 11.25, we get
n=9.
Plugging n=9 in 2nd equation.
m = 5(9)-5 = 45 -5 = 40.
Plugging n=9 and m=40 in first equation, we get
9 +40 +l = 90
49 +l = 90.
Subtracting 49 from both sides, we get
49-49 +l = 90-49
l = 41.
Therefore, sides are of lengths l = 41, m= 40 and n=9.
