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DIA [1.3K]
3 years ago
5

An employee is paid $12.50 per hour plus

Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0
The slope of the graph would be 12.50, or 12.5. You can rewrite this problem out to "y=12.5x+1.5". Since the rate at which the graph is changing is 12.5, that is the slope.
You might be interested in
Right Triangle Trig.
d1i1m1o1n [39]

The values are vx = \frac{14\sqrt{3} }{\sqrt{2} }, vw = \frac{14\sqrt{3} }{\sqrt{2} } and m∠x = 45°, for the given right angle diagram.

Step-by-step explanation:

The given is,

                Right angled triangle XVW,

                                     XW = 14\sqrt{3}

                                   m∠V = 90°

                                  m∠W = 45°

Step:1

              Given diagram is right angle triangle,

              Trigonometric ratios for right angle is,

                                 sin ∅ =\frac{Opp}{Hyp}............................(1)

                                  cos ∅ = \frac{Adj}{Hyp} .........................(2)

                                  tan ∅ = \frac{Opp}{Hyp}..........................(3)

Step:2

             For the value of VX,

                                   sin ∅ =\frac{VX}{XW}

            From given,

                               ∅ = 45°

                           XW = 14\sqrt{3}

           Above equation becomes,

                                     sin 45 =\frac{VX}{14\sqrt{3} }

            Where, Sin 45 = \frac{1}{\sqrt{2} },

                                            \frac{1}{\sqrt{2} } = \frac{VX}{14\sqrt{3} }

                                           VX = \frac{14\sqrt{3} }{\sqrt{2} }

Step:3

              For the value of VW,

                                   cos ∅ =\frac{VW}{XW}

            From given,

                               ∅ = 45°

                           XW = 14\sqrt{3}

           Above equation becomes,

                                     cos 45 =\frac{VW}{14\sqrt{3} }

            Where, cos 45 = \frac{1}{\sqrt{2} },

                                            \frac{1}{\sqrt{2} } = \frac{VW}{14\sqrt{3} }

                                           VW = \frac{14\sqrt{3} }{\sqrt{2} }

Step:4

             For the value m∠x = a,

                                      tan a =\frac{VX}{VW}

            From given,

                            VX = \frac{14\sqrt{3} }{\sqrt{2} }

                           VW = \frac{14\sqrt{3} }{\sqrt{2} }

           Above equation becomes,

                                     tan a =\frac{\frac{14\sqrt{3} }{\sqrt{2} } }           {\frac{14\sqrt{3} }{\sqrt{2} } }

                                      tan a = 1

                                             a = tan^{-1} (1)

                                             a = 45°

                                 m∠x = a = 45°

Step:5

            Check for solution,

                         m∠v  = m∠w + m∠x

                                   = 45° + 45°

                            90° =   90°

Result:

            The values are vx = \frac{14\sqrt{3} }{\sqrt{2} }, vw = \frac{14\sqrt{3} }{\sqrt{2} } and m∠x = 45°, for the given right angle diagram.

           

5 0
3 years ago
A triangle has a base of 7m and an area of 17.5 squared. What is the height?
Tresset [83]
The height is 5 meters :)
7 0
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You just got a free ticket for a boat ride, and you can bring along 2 friends! Unfortunately, you have 5 friends who want to com
Elena-2011 [213]

Answer:

10


Step-by-step explanation:


6 0
3 years ago
Costom duty of 30 % is charged when electrical item are imported. If 9000 rupees has to be paid as customs duty when an item of
suter [353]

Answer:

30,000 rupees

Step-by-step explanation:

Percentage of custom duty = 30%

Amount of custom duty = 9000 rupees

Let

x = value of the item which is being imported

30% of x = 9000 rupees

30/100 * x = 9000

0.3 * x = 9000

0.3x = 9000

x = 9,000/0.3

x = 30,000 rupees

x = value of the item which is being imported = 30,000 rupees

5 0
3 years ago
The square of 9 less than a number is 3 less than the number. What is the number?
dmitriy555 [2]
I think it’s maybe C
8 0
3 years ago
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