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saveliy_v [14]
3 years ago
5

The width of a telescope lens is measured to be 3 cm, but the actual size of the lens is 3.1 cm. What is the percent error in th

e
measurement?

0.3%
0.31%
3.3%
31%
Mathematics
1 answer:
dlinn [17]3 years ago
4 0

Answer:

31

Step-by-step explanation:

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I think 5 1/3 ft^2.
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Dave surveyed 80 7th-graders and 90 8th-graders. He found that about 75% of the 7th-graders like pop music, while 80% of the 8th
dimaraw [331]

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5 0
3 years ago
Right Triangle Trig.
d1i1m1o1n [39]

The values are vx = \frac{14\sqrt{3} }{\sqrt{2} }, vw = \frac{14\sqrt{3} }{\sqrt{2} } and m∠x = 45°, for the given right angle diagram.

Step-by-step explanation:

The given is,

                Right angled triangle XVW,

                                     XW = 14\sqrt{3}

                                   m∠V = 90°

                                  m∠W = 45°

Step:1

              Given diagram is right angle triangle,

              Trigonometric ratios for right angle is,

                                 sin ∅ =\frac{Opp}{Hyp}............................(1)

                                  cos ∅ = \frac{Adj}{Hyp} .........................(2)

                                  tan ∅ = \frac{Opp}{Hyp}..........................(3)

Step:2

             For the value of VX,

                                   sin ∅ =\frac{VX}{XW}

            From given,

                               ∅ = 45°

                           XW = 14\sqrt{3}

           Above equation becomes,

                                     sin 45 =\frac{VX}{14\sqrt{3} }

            Where, Sin 45 = \frac{1}{\sqrt{2} },

                                            \frac{1}{\sqrt{2} } = \frac{VX}{14\sqrt{3} }

                                           VX = \frac{14\sqrt{3} }{\sqrt{2} }

Step:3

              For the value of VW,

                                   cos ∅ =\frac{VW}{XW}

            From given,

                               ∅ = 45°

                           XW = 14\sqrt{3}

           Above equation becomes,

                                     cos 45 =\frac{VW}{14\sqrt{3} }

            Where, cos 45 = \frac{1}{\sqrt{2} },

                                            \frac{1}{\sqrt{2} } = \frac{VW}{14\sqrt{3} }

                                           VW = \frac{14\sqrt{3} }{\sqrt{2} }

Step:4

             For the value m∠x = a,

                                      tan a =\frac{VX}{VW}

            From given,

                            VX = \frac{14\sqrt{3} }{\sqrt{2} }

                           VW = \frac{14\sqrt{3} }{\sqrt{2} }

           Above equation becomes,

                                     tan a =\frac{\frac{14\sqrt{3} }{\sqrt{2} } }           {\frac{14\sqrt{3} }{\sqrt{2} } }

                                      tan a = 1

                                             a = tan^{-1} (1)

                                             a = 45°

                                 m∠x = a = 45°

Step:5

            Check for solution,

                         m∠v  = m∠w + m∠x

                                   = 45° + 45°

                            90° =   90°

Result:

            The values are vx = \frac{14\sqrt{3} }{\sqrt{2} }, vw = \frac{14\sqrt{3} }{\sqrt{2} } and m∠x = 45°, for the given right angle diagram.

           

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Line I is shown below<br> Right triangles A B C and DEF are drawn to measure the slope of the line
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Answer:

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3 years ago
Help me please. what is the solution for<br> 4≤n−4
notka56 [123]

Answer:

n\geq8

Step-by-step explanation:

You add 4 to both sides to make n the only thing on one side. Then to make the answer look better you move n to the left side and flip the symbol because n changed sides.

4\leq n-4\\ 4+4\leq n-4+4\\ 8\leq n\\ n\geq 8

7 0
3 years ago
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