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vesna_86 [32]
3 years ago
8

23891-18939 answer pls thanks

Mathematics
2 answers:
Tems11 [23]3 years ago
6 0

Merhaba ;))

Answer:

4.952

#Başarılar

olga55 [171]3 years ago
4 0

Answer:

<h2>4952</h2>

Step-by-step explanation:

\begin{matrix}\space\space&2&3&8&9&\textbf{1}\\ -&1&8&9&3&\textbf{9}\end{matrix}\\\mathrm{The\:bottom\:number\:is\:larger\:than\:the\:upper\:number.\:\:\\Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}\\\mathrm{Borrow\:}1\mathrm{\:from\:}9\mathrm{.\:\:The\:remainder\:is\:}8\\\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{8}&10\\ \space\space&2&3&8&\textbf{\linethrough{9}}&1\\ -&1&8&9&\textbf{3}&9\end{matrix}

\begin{matrix}\space\space&\space\space&\space\space&\space\space&8&\textbf{11}\\ \space\space&2&3&8&\linethrough{9}&\textbf{\linethrough{1}}\\ -&1&8&9&3&\textbf{9}\end{matrix}

\frac{\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{8}&11\\ \space\space&2&3&8&\textbf{\linethrough{9}}&\linethrough{1}\\ -&1&8&9&\textbf{3}&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{5}&2\end{matrix}}

\frac{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&8&11\\ \space\space&2&\textbf{3}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}

\frac{\begin{matrix}\space\space&\textbf{1}&10&\space\space&8&11\\ \space\space&\textbf{\linethrough{2}}&3&8&\linethrough{9}&\linethrough{1}\\ -&\textbf{1}&8&9&3&9\end{matrix}}{\begin{matrix}\space\space&\textbf{\space\space}&\space\space&\space\space&5&2\end{matrix}}

\frac{\begin{matrix}\space\space&1&\textbf{13}&\space\space&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{3}}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}

\frac{\begin{matrix}\space\space&1&\textbf{12}&10&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{13}}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}

\frac{\begin{matrix}\space\space&1&12&\textbf{18}&8&11\\ \space\space&\linethrough{2}&\linethrough{13}&\textbf{\linethrough{8}}&\linethrough{9}&\linethrough{1}\\ -&1&8&\textbf{9}&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{\space\space}&5&2\end{matrix}}

\frac{\begin{matrix}\space\space&1&12&\textbf{18}&8&11\\ \space\space&\linethrough{2}&\linethrough{13}&\textbf{\linethrough{8}}&\linethrough{9}&\linethrough{1}\\ -&1&8&\textbf{9}&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{9}&5&2\end{matrix}}

\frac{\begin{matrix}\space\space&1&\textbf{12}&18&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{13}}&\linethrough{8}&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{4}&9&5&2\end{matrix}}

\frac{\begin{matrix}\space\space&\textbf{1}&12&18&8&11\\ \space\space&\textbf{\linethrough{2}}&\linethrough{13}&\linethrough{8}&\linethrough{9}&\linethrough{1}\\ -&\textbf{1}&8&9&3&9\end{matrix}}{\begin{matrix}\space\space&\textbf{0}&4&9&5&2\end{matrix}}\\\\=4952

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Answer:

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Step-by-step explanation:

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S_A_V [24]

Answer:

22in²

Step-by-step explanation:

According to the scenario, computation of the given data are as follows,

Circumference = 25 (1/7)

As we know,

Circumference of a circle = 2πr

By solving this we get

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Now. we can calculate the area by using following formula,

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By putting the value, we get

Area = (22/7) × 4²

=  22/7 × 16

= 352÷16

Area = 22in²

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What is the area of a triangle with a base of 7 units and a height of 11 units?
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B

Step-by-step explanation:

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