Answer:
2 x - y = - 2 and 22 x + 10 y = 7
Step-by-step explanation:
To find the equation to produce a solution of approximately (–0.3, 1.4), we have to solve the equations simultaneously.
a) For line 2 x - y = - 2 and 22 x + 10 y = 7
Multiply line 1 by 10 to give : 20x - 10y = -20
Add 20x - 10y = -20 and 22 x + 10 y = 7 to get:
42x = -13
x = -13/42 = -0.3
Put x = -0.3 in 2 x - y = - 2 to get:
2(-0.3) - y = - 2
-0.6 - y = -2
y = 2 - 0.6 = 1.4
x = - 0.3 and y = 1.4
This is the correct option
b) For line 3 x + 2 y = 5 and 4 x - y = 2
Multiply line 2 by 2 to give : 8x - 2y = 8
Add 8x - 2y = 48 and 3 x + 2 y = 5 to get:
11x = 13
x = 13/11 = 1.2
Put x = 1.2 in 3 x + 2 y = 5 to get:
3 (1.2) + 2 y = 5
y = 1.4
x = 1.2 and y = 1.4
c) For line 4 x - y = 2 and 22 x + 10 y = 7
Multiply line 1 by 10 to give : 40x - 10y = 20
Add 40x - 10y = 20 and 22 x + 10 y = 7 to get:
62x = 27
x = 0.44
Put x = 0.44 in 4x - y = 2 to get:
y = -0.24
d) For line 2 x - y = - 2 and 3 x + 2 y = 5
Multiply line 1 by 2 to give : 4x - 2y = -4
Add 4x - 2y = -4 and 3x + 2 y = 5 to get:
7x = 1
x = 0.14
Put x = 0.14 in 2 x - y = - 2 to get:
y = 2.28
