1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
y = 2/3(z)(7 - x^2)
2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz
Answer:
k = 15.94
Step-by-step explanation:
Let us solve this system of equations by using the elimination method. Adding the 2 equations, we get
9x + 5y - 9x + 4y = -33 + 6
9y = -27
y = -3
Substituting this value of y in the first equation, we get
-9x + 4(-3) = 6
-9x - 12 = 6
9x + 12 = -6
9x = -18
x = -2
Therefore, x = -2, and y = -3. Hope this helps! If you have any questions, feel free to ask.
