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Liono4ka [1.6K]
4 years ago
14

Plsss trueieirolfkgkfkf

Mathematics
1 answer:
attashe74 [19]4 years ago
4 0
3x-5=5x-17
-2x-5=-17
-2x=-12
X=6
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The correct answer is b
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a triangle that is very special to you has an area of 12 square feet. The height of this figure is six feet. What is the length
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The length of the base is 4
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Place (dlick and drag) one option from each of the lists below Into Its corresponding box to
earnstyle [38]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{3}}x+5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-1}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-1}\implies 3}}

so we're really looking for the equation of a line whose slope is 3 and passes through (1 , 10)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{10})\qquad \qquad \stackrel{slope}{m}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{3}(x-\stackrel{x_1}{1}) \\\\\\ y-10=3x-3\implies y=3x+7

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alex41 [277]
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4 0
3 years ago
-2x + 4 = -3x + 4<br> 3<br> One Solution<br> No Solution<br> Infinite Solutions
iogann1982 [59]

Answer:

X=0 or no solution

Step-by-step explanation:

-2x+4=-3x+4

cancel equal terms on both sides of the equation

-2x=-3x

move the variable to the left-hand side and change its sign

-2x+3x=0

collect like terms

x=0

6 0
3 years ago
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