Question

What is the rate of change of the volume of the cylinder at that instance (in cubic kilometers per second)?

Answer 1

Answer:

hello your question is incomplete attached below is the complete question

answer : -2400 π

Step-by-step explanation:

dr/dt = -12 km/s

h = 2.5 km

r = 40 km at some instant

hence the rate of change of Volume of cylinder at that instance

= dv / dt = $d(\pi r^h ) / dt$  

              = $\pi h\frac{d(r^2)}{dt}$  = $-\pi h *2r *dr/dt$

hence ; dv / dt = -2400 π