Answer:
(x, y) = (40, 30)
Step-by-step explanation:
A graphing calculator can show you the solution to this system of equations is (x, y) = (40, 30). That is the point of intersection where the two lines cross.
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An algebraic solution can be found by using the substitution method. An expression for y can be found using the second equation:
y = 110 -2x . . . . . . subtract 2x from both sides
Using this in the first equation gives ...
3x -4(110 -2x) = 0 . . . . substitute for y
11x = 440 . . . . . . . . . simplify, add 440
x = 40 . . . . . . . . . . divide by 11
y = 110 -2(40) = 30
The solution is (x, y) = (40, 30).
Well, the first step would be to multiply everything out. 1*2=2, g1*i=i, g2i*2=4i, and 2i*i=2i^2. This would bring the equation to 2+i+4i+2i^2=5(2+i)
Next, multiply the other side. 5*2=10, and 5*i=5i. The equation is now:
2+i+4i+2i^2=10+5i
Now, combine like terms, and arrange the sides from highest exponents to lowest exponents: i+4i=5i. You can arrange the equation to 2i^2+5i+2=5i+10.
Subtract 2 from both sides: 2i^2+5i=5i+8
Subtract 5i from both sides: 2i^2=8
Divide both sides by 2: i^2=4.
Finally, find the square root of 4 to get i. The square root of 4 is 2, so i=2.
Answer:
BC = 1.71
Step-by-step explanation:
well to start we have to know the relationship between angles, legs and the hypotenuse in a right triangle
α = 70°
a: adjacent = BC
h: hypotenuse = 5
sin α = o/h
cos α= a/h
tan α = o/a
we see that it has (angle, adjacent, hypotenuse)
we look at which meets those data between the sine, cosine and tangent
is the cosine
cos α = a/h
Now we replace the values and solve
cos 70 = a/5
0.34202 = a/5
0.34202 * 5 = a
1.7101 = a
round to the neares hundredth
a = 1.7101 = 1.71
BC = 1.71
Answer:
The relation is not a function.
