Landslides often accompany earthquakes and volcanoes and pose an additional threat to humans after these events.

Case Project 2-1: The Differences Between IPv4 and IPv6 You are a network engineer for an IT consulting firm named F1IT. One of

Nadusha1986 [10]

Answer:

Following are the difference to this question:

Explanation:

IPv4:

The $IPv_4$ is uses the packet changed method, that is a Link Layer networks(like Ethernet). It has 4.3 billion addresses capacity. It uses the 32-bit logical device address, that written in decimal language. It is divided by 4 bytes E.g. 192.168.1.1

The host part and network part are 2 parts. For a network, the host part may vary, while for the entire subnet, the network part remains equal. The scheme of 232 addresses is available on application depends on security.

IPv6:

The IPv6 is used in the internet protocoland it is higher than IPv4. It can provide endless number Opf addresses, and use to solves the problem of IPv4 exhaustion and satisfies the demand for rising networking.

IPv4 Substitutor Built to meet more IP address requirements. In the Logical address of 128-bit Written hexadecimally and with colons divided, and the Space of 128 addresses are required. IPsec is an integrated security feature.

5 0

3 years ago

What happens when a basic text file without any HTML code is opened in a web browser?

Korvikt [17]

Answer:

The text will be shown without any formatting.

Explanation:

3 0

3 years ago

Read 2 more answers

14. Write a program that accepts or rejects applicants for admission at Fictional University. To qualify, an applicant must be a

Gala2k [10]

The required program for applicant selection written in python 3 is :

age = int(input())

grade12_avg = int(input())

ps = int(input())

cs = int(input())

def status(age, grade12_avg, ps, cs):

msg = 'sorry you are not admitted'

if (age >=16) and (grade_avg >=60):

if (ps>=65) or (cs>=50):

message = 'congratulations'

print(message)

else :

print(message)

else:

print(message)

Run through of the codeblock :

age = int(input())

grade12_avg = int(input())

ps = int(input())

cs = int(input())

# input values provided by users

.

def status(age, grade12_avg, ps, cs):

#Define a function named status

msg = 'sorry you are not admitted'

# display message for recepients

if (age >=16) and (grade_avg >=60):

#First condition ; the and keyword means both must be True

if (ps>=65) or (cs>=50):

2nd condition, or statement means only one or both can be true

message = 'congratulations'

#content of message if both conditions are met

print(message)

#Display newly defined content of message

else :

print(message)

#Display initial content of message

else:

print(message)

#Display initial content of message.

Learn more :brainly.com/question/24672775

7 0

2 years ago

Research three different distributions of Linux on the Internet. Record where you went to obtain your information. Compare and c

VARVARA [1.3K]

Answer:

The three Linux distributions are Arch Linux, Ubuntu and Fedora. In order to get more detailed information go to the wikipedia page of comparision of linux distributions.

Strengths and Features of these three are attached.

The two linux newsgroups are

1) Comp.os.linux.announce

2)comp.os.linux.networking

Explanation:

6 0

3 years ago

Matching parentheses. An math expression may have a number of parentheses like (, ), [, ], { and }. Each openning parenthesis (,

Solnce55 [7]

C++ Code

#include
using namespace std;

bool match(const char exp[],const int s)
{
// declare a character array to perform stack operations
char stack[s];

// declare top and initialize to -1 and flag to 0
int top=-1,i,flag=0;

// visit all characters in the expression string
for(i=0;i {
// if the character is [ or ( or { then push it into stack
if(exp[i]=='[' || exp[i]=='(' || exp[i]=='{')
{
top++;
stack[top]=exp[i];
}
// if the character is ] or ) or } then check conditions
else if(exp[i]==']' || exp[i]==')' || exp[i]=='}')
{
// check stack is empty or not
if(top!=-1)
{
// check all possible failure conditions
if(exp[i]==')' && (stack[top] == '{' || stack[top]=='['))
{
flag = 1;
break;
}
else if(exp[i]==']' && (stack[top] == '{' || stack[top]=='('))
{
flag = 1;
break;
}
else if(exp[i]=='}' && (stack[top] == '(' || stack[top]=='['))
{
flag = 1;
break;
}
top--;
}
else
{
flag=1;
break;
}
}
}
// after visiting all characters of expression string check if stack is not empty and flag is 1. if any one of the condition is true return false. otherwise return true

if(top>=0 || flag==1)
return false;
else
return true;
}

int main()
{

// declare character array to store expression
char exp[10000];
cout<<"Enter an Expression"<
// read expression from user
cin.getline(exp, 10000);
int s=0;

// find the length of the expression string
for(int i=0;exp[i]!='\0';i++)
{
s++;
}

// call the match function
bool status = match(exp,s);

// print the result based on value returned by match() function
if(status == 1)
cout<<"true"< else
cout<<"false"<
}

Sample Input/Output is attached

3 0

2 years ago