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weeeeeb [17]
3 years ago
15

Diagnosing is solving the problem, and trouble shooting is figuring out what the problem is.

Computers and Technology
1 answer:
exis [7]3 years ago
3 0
False its the opposite
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To test for the current date in a query, type ____ in the criteria row of the appropriate column.
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zxc

Explanation:

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30 POINTS Conduct Interviews
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g Suppose we want to compress a text consisting of 6 characters,a, b, c, d, e, fusingthe Huffman Algorithm. Give an example for
Papessa [141]

Answer:

e(a) = 0

e(b) = 10

e(c) = 110

e(d) = 1110

Explanation:

The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).

Where f(x) is frequency of character x.

Lets consider the scenario when

f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005

Please see attachment for image showing the steps of construction of Huffman tree:- see attachment

From the Huffman tree created, we can see that endcoding e() of each character are as follows:-

e(a) = 0

e(b) = 10

e(c) = 110

e(d) = 1110

e(e) = 11110

e(f) = 11111

So we can see that maximum length of encoding is 5 in this case.

3 0
3 years ago
please help, touch pad and trackpad are the same thing and the other answers don’t really make sense to me..
WINSTONCH [101]

Answer:

The answer to the problem is B

8 0
2 years ago
Write a python program to read four numbers (representing the four octets of an IP) and print the next five IP addresses. Be sur
sdas [7]

Answer:

first_octet = int(input("Enter the first octet: "))

second_octet = int(input("Enter the second octet: "))

third_octet = int(input("Enter the third octet: "))

forth_octet = int(input("Enter the forth octet: "))

octet_start = forth_octet + 1

octet_end = forth_octet + 6

if (1 <= first_octet <= 255) and (0 <= second_octet <= 255) and (0 <= third_octet <= 255) and (0 <= forth_octet <= 255):

   for ip in range(octet_start, octet_end):

       forth_octet = forth_octet + 1

       if forth_octet > 255:

           forth_octet = (forth_octet % 255) - 1

           third_octet = third_octet + 1

           if third_octet > 255:

               third_octet = (third_octet % 255) - 1

               second_octet = second_octet + 1

               if second_octet > 255:

                   second_octet = (second_octet % 255) - 1

                   first_octet = first_octet + 1

                   if first_octet > 255:

                       print("No more available IP!")

                       break

       print(str(first_octet) + "." + str(second_octet) + "." + str(third_octet) + "." + str(forth_octet))

else:

   print("Invalid input!")

Explanation:

- Ask the user for the octets

- Initialize the start and end points of the loop, since we will be printing next 5 IP range is set accordingly

- Check if the octets meet the restrictions

- Inside the loop, increase the forth octet by 1 on each iteration

- Check if octets reach the limit - 255, if they are greater than 255, calculate the mod and subtract 1. Then increase the previous octet by 1.

For example, if the input is: 1. 1. 20. 255, next ones will be:

1. 1. 21. 0

1. 1. 21. 1

1. 1. 21. 2

1. 1. 21. 3

1. 1. 21. 4

There is an exception for the first octet, if it reaches 255 and others also reach 255, this means there are no IP available.

- Print the result

8 0
3 years ago
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