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PolarNik [594]
3 years ago
5

Select the statement which best fits the justification for the step in Line 5.

Mathematics
2 answers:
kipiarov [429]3 years ago
7 0

Answer:

Simplify

Step-by-step explanation:

zvonat [6]3 years ago
4 0

Do you know the answer???


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A  =  {cos}^{ - 1} 0.5 \\  \:  \:   A= 60

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If a scalene triangle has its measures 4 m, 11 m and 8 m, find the largest angle.
soldier1979 [14.2K]

Answer:

129.8 approximately

Step-by-step explanation:

So this sounds like a problem for the Law of Cosines. The largest angle is always opposite the largest side in a triangle.

So 11 is the largest side so the angle opposite to it is what we are trying to find. Let's call that angle, X.

My math is case sensitive.

X is the angle opposite to the side x.

Law of cosines formula is:

x^2=a^2+b^2-2ab \cos(X)

So we are looking for X.

We know x=11, a=4, and b=8 (it didn't matter if you called b=4 and a=8).

11^2=4^2+8^2-2(4)(8)\cos(X)

121=16+64-64\cos(X)

121=80-64\cos(X)

Subtract 80 on both sides:

121-80=-64\cos(X)

41=-64\cos(X)

Divide both sides by -64:

\frac{41}{-64}=\cos(X)

Now do the inverse of cosine of both sides or just arccos( )

[these are same thing]

\arccos(\frac{-41}{64})=X

Time for the calculator:

X=129.8 approximately

3 0
3 years ago
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