45 dimes and 93 nickels were in bank
<em><u>Solution:</u></em>
Let "n" be the number of nickels
Let "d" be the number of dimes
We know that,
value of 1 nickel = $ 0.05
value of 1 dime = $ 0.10
<em><u>Given that There are three more than twice as many nickels as there are dimes</u></em>
Number of nickels = 3 + 2(number of dimes)
n = 3 + 2d ---- eqn 1
<em><u>Also given that coin bank that excepts only nickels and dimes contains $9.15</u></em>
number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15
0.05n + 0.10d = 9.15 ---- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 1 in eqn 2
0.05(3 + 2d) + 0.10d = 9.15
0.15 + 0.1d + 0.10d = 9.15
0.2d = 9
<h3>d = 45</h3>
From eqn 1
n = 3 + 2(45)
n = 3 + 90 = 93
<h3>n = 93</h3>
Thus 45 dimes and 93 nickels were in bank
B.!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
6:20=9:30=3:10=18:60=16:160/3=12:40
Step-by-step explanation:
The question requires you to find value of x in the ratios given;
Start with the first pair
6:20 = 9:x
6/20 =9/x
6x=20*9
6x=180
x=180/6=30 ⇒⇒ 6:20 = 9:30
The second pair after replacing the value of x=30 will be
9:30 = x:10
9/30=x/10
90=30x
90/30 =x
3=x⇒⇒ 9:30 = 3:10
The third pair after replacing value of x=3 will be
3:10 =x:60
3/10 =x/60
180=10x
180/10 =x
18=x ⇒⇒ 3:10 = 18:60
The fourth pair after replacing value of x=18 will be;
18:60 = 16:x
18/60 = 16/x
18x=16*60
x= (16*60)/18 =160/3
x= 160/3 ⇒⇒⇒ 18:60 = 16: 160/3
The firth pair after replacing value of x=160/3 will be;
16: 160/3 =12:x
16x= 160/3 *12
16x = 160 * 4
x= (160 *4 )/16
x=40
⇒⇒ 16: 160/3 = 12: 40
Learn More
Ratios and proportions :brainly.com/question/9512748
Keywords : ratio, value of x, proportion
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The problem is about converting a decimal into a fraction, and simplify it:
<span>0.40 = 0.4 = four tenths = 4/10 = 2/5
that is the simplest fraction</span>
Answer:
6x^2+12x+29+50/x-2
Step-by-step explanation:
