Determine the quadratic equation in standard form of a parabola with a zero at x=5 and vertex ar (-3, 32). start with factored f
1 answer:
Answer:
see image...
start with Graphing Form: y = a(x-h)²+ k
knowing that h is the x value (negative of it) of the vertex , and k is the y value of the vertex
Graphing Form Equation: y = a(x+3)²+32
you are also given that when the x value is 5 the y value has to be 0
0 = a(4)^2 + 32
a has to be - 1/2
Step-by-step explanation:
You might be interested in
The derivative is given by the limit
You have
Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.
By this identity, you have
So in the limit you get
The first two limits are both 1, and the single term in the last limit approaches 0 as
which agrees with the result you get from applying the chain rule.