Given that the minimum value is 4, find the value of k

Mathematics

1 answer:

finlep [7]2 years ago

5 0

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Solve x+2/x-4<0<br><br> A)–4 < x < –2<br> B)–2 < x < 4<br> C)–2 < x < –4

Gelneren [198K]

$Domain:\ x\neq-2\\\\\dfrac{x+2}{x-4}$

Other method:

$\dfrac{x+2}{x-4}$

zeros of numerator and denominator are x = -2 and x = 4.

Look at the second picture.

for x < -2 → x + 2 < 0 and x - 4 < 0

therefore $\dfrac{x + 2}{x - 4}=\dfrac{(-)}{(-)}>0$

for -2 < x < 4 → x + 2 > 0 and x - 4 < 0

therefore $\dfrac{x+2}{x-4}=\dfrac{(+)}{(-)} < 0$

for x > 4 → x + 2 > 0 and x - 4 > 0

therefore $\dfrac{x+2}{x-4}=\dfrac{(+)}{(+)} > 0$

<h3>Answer: B) -2 < x < 4</h3>

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2 years ago

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klasskru [66]

Answer:
c
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6 0

3 years ago

Julio has started his very own floral business. He sells centerpieces for $19.50 each. His fixed costs are $500 per month, and e

Phantasy [73]

The total cost, C, is the sum of the cost to produce the centerpieces and the fixed cost. The equation for C is C = 8n + 500.

The total revenue, R, of Julio's floral business is the product of the cost per centerpiece and the number of centerpieces sold. The equation for R is R = 19.50n.

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3 years ago

Read 2 more answers

What are the amplitude, period, and phase shift of the given function? f(t)=-1/2sin(3t-2pi)

Romashka [77]

Answer:

The $amplitude=|A|=\frac{1}{2}$ , $period=3$ and $\text{phase shift}=\frac{2\pi}{3}$ .