Step-by-step explanation:
5x2-40
5(x2-8)
i hope it helps
Answer:
The fossil is 1860 years old.
Step-by-step explanation:
The equation for the amount of fossil has the following format:

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.
Half-life of c-14 is 5730 years.
This means that 
So







So

How old is the fossil?
This is t for which

So







The fossil is 1860 years old.
Answer:

Step-by-step explanation:
Use the slope-intercept form:

m is the slope and b is the y-intercept. Looking at the graph, you can find the y-intercept. The y-intercept is the point where x equals 0:


To find the slope, take any two points from the line:

Use the slope formula for when you have two points:

The rise over run is the change in the y-axis over the change of the x-axis. Insert the appropriate values:


Simplify parentheses (two negatives makes a positive):


Simplify (two negatives make a positive):

The slope is
and the y-intercept is
. Insert these into the equation:

Finito.
Answer:
the first one is right and other are wrong
Answer:
14.2
Step-by-step explanation: