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3 years ago

What is the chance that a human zygote will receive?

Biology

1 answer:

Sladkaya [172]3 years ago

5 0

I think there's a %50 chance it will receive

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Which are the following statements are TRUE when concerning cells?

labwork [276]

Answer:

I think it will option b hope it helps

3 0

3 years ago

There are a total of ______ state(s) of matter. <br> a. 1 <br> b. 2 <br> c. 3 <br> d. 4

Lilit [14]

There are 4 states of matter : plasma, liquid, gas and solid.

7 0

4 years ago

The answer is 51.0 ml but can someone explain why please

professor190 [17]

Answer:

$\boxed{\sf A. \ 51 \ mL}$

Explanation:

Amount of water displaced by the sphere will be equal to the volume of complete sphere.

As the sphere completely sinks to the bottom of the cup.

We have been given;

Diameter of sphere (d) = 4.6 cm

So,

$\sf Radius \: of \: sphere \: (r) = \frac{Diameter \: of \: sphere \: (d)}{2} \\ \sf = \frac{4.6}{2} \\ \sf = 2.3 \: cm$

Volume of sphere (V):

$\boxed{ \bold{V = \frac{4}{3} \pi {r}^{3} }}$

By substituting value of r we get:

$\sf \implies V = \frac{4}{3} \times \pi \times {(2.3)}^{3} \\ \\ \sf \implies V = \frac{4}{3} \times 3.14 \times 12.167 \\ \\ \sf \implies V = \frac{152.81752}{3} \\ \\ \sf \implies V = 50.94 \: {cm}^{3} \\ \\ \sf \implies V \approx 51 \: {cm}^{ 3}$

1 cm³ = 1 mL

$\therefore$

V = 51 mL

So,

Water displaced by the sphere = 51 mL

6 0

3 years ago

Margo was adopted when she was an infant. Her adoptive parents' intelligence test scores are in the average range, while her bio

irina1246 [14]

It will be more similar to her biological parents test scores

4 0

3 years ago

Read 2 more answers

Why does synthetically produced RNase refold incorrectly if the reducing agent is removed before urea removal?

olya-2409 [2.1K]

<h2>Disulfide bonds interaction </h2>

Explanation:

The high concentration of urea causes unfolding of protein and thus results in loss of function of a protein. The urea interacts with the protein and prevents the folding of a protein.
During oxidation, the disulfide bonds that are required for proper functioning and stabilization of protein are formed, while in the presence of urea, the disulfide bonds are not positioned correctly. The protein oxidation results in covalent modification of a protein that results in the change of physical and chemical properties of a protein.
The change of physical and chemical properties of protein after oxidation and in the presence of urea cannot be modified even after the removal of urea. Thus, protein does not fold properly.
Hence the right answer is "disulfide bonds are not positioned correctly rather than week bonding interaction"

6 0

3 years ago