M<ACD = 100
m<B = 60
so
m<ACB = 180 - m<ACD
m<ACB = 180 - 100
m<ACB = 80
m<A = 180 - (60 + 80)
m<A = 180 - 140
m<A = 40
Answer:
you did not add the fractions I will answer tho just put the fractions in the. comments in this. format 1/2
Answer:
Average time for West Middle was maximum.
Step-by-step explanation:
Average time for a track meet for schools =
For Eastbay Middle,
Average time per mile =
= 6 minutes per mile
For Northwest Middle,
Average time =
= 5 minutes per mile
For South Central Middle,
Average time =
= 7 minutes per mile
For West Middle,
Average time =
= 8 minutes per mile
Therefore, average time for West Middle (8 minutes per minute) was maximum.
Answer: 1,8, square root of 65
Step-by-step explanation: