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3 years ago

1 + 1? .......……………………

Mathematics

2 answers:

Xelga [282]3 years ago

5 0

That’s rlly hard bro - @lincolnpalmerr ig

masya89 [10]3 years ago

4 0

Hmm difficult one but I think ima have to go with 2?????

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Joe and grace are baking cookies they need a total of 2 cups of sugar for the recipe joe has 11/10 cups of sugar and grace has 3

DanielleElmas [232]

Answer:

Step-by-step explanation:

Total amount of sugar needed to bake the cookies is 2 cups. Amount of sugar that Joe has is 11/10 cups of sugar. Amount of sugar that Grace has is 3/4 cups of sugar.

The total amount of sugar that Joe and Grace have won't be enough to bake the cake because the total of 11/10 cups and 3/4 cups is below 2 cups

6 0

3 years ago

What is the correct answer for this equation here?<br>3(4x – 7) = 135

S_A_V [24]

Answer:

x=13

Step-by-step explanation:

1. divide both sides by 3

2. simplify: 4x-7=45

3. add 7 to both sides

4. 4x=52

5. divide both sides by 4

6. x=13

7 0

3 years ago

HELP ASAP!! Identify the matrix transformation of ΔPQR, which has coordinates P(−5, −2),Q(−6, −3), and R(−2, −3), for reflection

podryga [215]

Answer:

Matrix transformation = $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ .

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-5\\-2\end{array}\right]$ = (5,-2)

Q'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-6\\-3\end{array}\right]$ = (6,-3)

R'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-2\\-3\end{array}\right]$ = (2,-3)

3 0

2 years ago

A shopkeeper bought 50 kg of sugar and sold 1/4th of the sugar. find the mass of sugar that was left

soldi70 [24.7K]

Answer:

12.5 kg

Step-by-step explanation:

50 divided by 4 = 12.5

6 0

3 years ago

Read 2 more answers

What is the value of x?

frez [133]

$\left\{\begin{array}{ccc}x+2y=4&\text{multiply both sides by 5}\\4x-5y=42&\text{multiply both sides by 2}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}5x+10y=20\\8x-10y=84\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad13x=104\qquad\text{divide both sides by 13}\\\\\boxed{x=8}\\\\Answer:\ \boxed{\boxed{x=8}}$

5 0

2 years ago