Answer:
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Answer:
3x^2+2x+15
Step-by-step explanation:
3x^2+2x+2+(4x2)+5
use pemdas
Since F(X) = 3^X,
F(4) = 3^4 = 81
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Step-by-step explanation:
if the two integers are x and y
xy=-10
x+y=-9
x+(-10/x)=-9
x2+9x-10=0
(x-1)(x+10)=0
x=1 or x=-10
if x=1, y=-10
if x=-10, y=1
so the two integers are 1 and -10