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2 years ago

M=8+n PLZ HELP ASAP, WILL MARK BRAINLIEST!!!

Mathematics

1 answer:

irina [24]2 years ago

5 0

$\\ \qquad\quad\sf\longmapsto m=8+n$

Take n to left

$\\ \qquad\quad\sf\longmapsto m-n=8$

Hence

if m=1

$\\ \qquad\quad\sf\longmapsto n=m-8=1-8=-7$

if n=1

$\\ \qquad\quad\sf\longmapsto m=8+1$

$\\ \qquad\quad\sf\longmapsto m=9$

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Answer:

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3b) P=0.153

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Step-by-step explanation:

(1) H0: p = 0.3 vs Ha: p ≠ 0.3. In their survey, they had a count of 38 using a sample size n=100.

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1b) The standard deviation is

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The sample size is n=100.

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As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.74 is P=0.08.

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The sample size is n=500.

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As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=3 is P=0.0027.

2c) The null hypothesis is rejected.

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2b) The standard deviation is

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The sample size is n=200.

The z-value is:

$z=\frac{\hat{p}-p}{\sigma}=\frac{0.55-0.6}{0.035}=\frac{-0.05}{0.035}=-1.43$

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.43 is P=0.153.

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2 years ago

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which leads to the system of linear equations,

$\begin{cases} 2c_1 + 3c_2 + c_3 = 0 \\ -c_1 + c_2 + 2c_3 = 0 \\ c_1 + c_2 = 0 \end{cases}$

From the third equation, we have $c_1=-c_2$ , and substituting this into the second equation gives

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and in turn, $c_1=c_3$ . Substituting these into the first equation gives

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Evgen [1.6K]

<h3>Answer: D) 31</h3>

==========================================================

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Let's compute f(2)

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f(x) = 4x^3 - 10

f(x) = 4(x)^3 - 10

f(2) = 4(2)^3-10

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f(2) = 32-10

f(2) = 22

Now we'll plug this into the g(x) function

This is because g(f(2)) = g(22). I've replaced f(2) with 22

So,

g(x) = (3x-4)/2

g(22) = (3*22-4)/2

g(22) = (66-4)/2

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