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3 years ago

Reflect the point (4,1) over the line x=-2. What would the image point be?

2 answers:

6 0

(4,-5) of you graph it, you will see that the point is only 3 units away from -2 so you do the same to reflect it and you’ll get -5.

Cloud [144]3 years ago

5 0

Answer:

(-8, 1)

Step-by-step explanation:

x = -2 is a vertical line passing through (-2, 0).

The point (4, 1) is 6 units to the right of this line.

After reflecting the point over the line, the image point will be 6 units to the left of the line: (-8, 1).

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Order each set of numbers from least to greatest.<br><br><br> PLZ HELP ASAP

Wittaler [7]

Answer:

$\frac{41}{3} < 14 < \sqrt{200}$

<u> $0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} }$ </u>

Step-by-step explanation:

$\sqrt{200} = 10 \sqrt{2} = 14.1 \\ 14 = 14 \\ \frac{41}{3} = 13.6$

So ;

$\frac{41}{3} < 14 < \sqrt{200} \\ 13.6 < 14 < 14.1$

$\frac{2}{3} = 0.66 \\ \sqrt{ \frac{9}{16} } = \frac{3}{4} = 0.75 \\ 0.6 = 0.6$

So ;

$0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} } \\ 0.6 < 0.66 < 0.75$

I hope I helped you^_^

6 0

2 years ago

Find the length of the line PA.

Diano4ka-milaya [45]

RO divides the rectangle into two congruent right triangles.

The area of the one triangle is equal half area of the rectangle.

Calculate the area of rectangle:

$A_R=lw\\l=12,\ w=5\\\\A_R=12\cdot5=60$

The area of right triangle:

$A_T=\dfrac{1}{2}A_R\to A_T=\dfrac{1}{2}\cdot60=30$

Use the Pythagorean theorem to calculate the length of RO:

$|RO|^2=5^2+12^2\\\\|RO|^2=25+144\\\\|RO|^2=169\to|RO|=\sqrt{169}\to|RO|=13$

The formula of an area of this right triangle is:

$A_T=\dfrac{1}{2}|RO||PA|$

Therefore we have the equation:

$\dfrac{1}{2}(13)|PA|=30\qquad|\cdot2\\\\13|PA|=60\quad|:13\\\\|PA|=\dfrac{60}{13}\\\\|PA|\approx4.62$

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saul85 [17]

Answer:

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Step-by-step explanation:

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