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3 years ago

What is the greatest common factor of 18, 6, and 36?

Mathematics

2 answers:

Basile [38]3 years ago

5 0

Answer:

There are 6 common factors of 18 and 36, that are 1, 2, 3, 6, 9, and 18. Therefore, the greatest common factor of 18 and 36 is 18.

Step-by-step explanation:

Viktor [21]3 years ago

3 0

Answer:

18 is the greatest common factor between those

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nikitadnepr [17]

Write the ictter of the correct answer in the box containing the exercise number. If the answer has a shade in the box

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3 years ago

Match the real-world problem to its constant of proportionality.

OleMash [197]

Answer:

6.12

1.39

4.12

Step-by-step explanation:

If y ∝ x, then y = kx.

So, the constant of proportionality is given by $k = \frac{y}{x}$

Case 1:

$18.36 for 3 pizzas

Therefore, the constant of proportionality is $\frac{18.36}{3} = 6.12$

Case 2:

$4.17 for 3 pounds of bananas.

Hence, the constant of proportionality is $\frac{4.17}{3} = 1.39$

Case 3:

$16.48 for 4 pounds of potatoes.

Hence, the constant of proportionality is $\frac{16.48}{4} = 4.12$

Case 4:

2 cups of flour to make 24 cookies.

Hence, the constant of proportionality is $\frac{24}{2} = 12$ (Answer)

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3 years ago

Divide, 24x^6 - 12x^3 divided by 4x^3 Simplify as much as possible

LekaFEV [45]

24x6=24-(12x3)-12 divided 4x3is 12
The awnser:0

Hope it help

3 0

3 years ago

Determine the equation from the table listed below Will give Brainly

yanalaym [24]

Answer:

It's c) y = 15x +200

Step-by-step explanation:

First divide the total cost by the number of students using two values of the table:

1500/100 = 15

This is the number that multiply x in the equation.

In the options given, there is just one equation that have 15 multipling x, so that must be the answer

5 0

3 years ago

Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is running, he goes from 70

kumpel [21]

Answer:

His acceleration is $\frac{1}{15}$ meters per seconds²

Step-by-step explanation:

Acceleration is the rate of change of the speed

The formula of acceleration is $a=\frac{v_{f}-v_{i}}{t}$ , where

$v_{f}$ is the final speed
$v_{i}$ is the initial speed
The unit of the acceleration is meters/second²

∵ Jim goes from 70 meters/minute (beginning speed) to

106 meters/minute (final speed) in 9 seconds

∴ His initial speed $v_{i}$ = 70 meters/minute

- Change it the meter per second

∵ 1 minute = 60 seconds

∴ $\frac{70}{(1)(60)}=\frac{70}{60}=\frac{7}{6}$ meters/second

∴ $v_{i}$ = $\frac{7}{6}$ meters/second

∵ His final speed $v_{f}$ = 106 meters/minute

- Change it the meter per second

∴ $\frac{106}{(1)(60)}=\frac{106}{60}=\frac{53}{30}$ meters/second

∴ $v_{f}$ = $\frac{53}{30}$ meters/second

∵ The time of the change of his speed is 9 seconds

∴ t = 9

∵ The formula of acceleration is $a=\frac{v_{f}-v_{i}}{t}$

- Substitute the values of t, $v_{i}$ and $v_{f}$ in the formula above

∴ $a=\frac{\frac{53}{30}-\frac{7}{6}}{9}=\frac{1}{15}$

∴ His acceleration is $\frac{1}{15}$ meters per seconds²

3 0

3 years ago