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ale4655 [162]
3 years ago
8

8X=35 WHAT IS THE VALUE FOR X THAT MAKES THE EQUATION TRUE?

Mathematics
2 answers:
kenny6666 [7]3 years ago
5 0

Answer:

x= 35/8 or 4 3/8

Step-by-step explanation:

8X=35

/8    /8

x= 35/8

x= 4 3/8

AlladinOne [14]3 years ago
3 0
X = 4.375 you get this by dividing both sides by 8 so 35/8 gets you 4.375
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Drag and drop the constant of proportionality into the box to match the equation.
podryga [215]
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3 years ago
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Translate this sentence into an equation. 62 is the sum of 12 and Chrissy's age. Use the variable c to represent Chrissy's age.
Greeley [361]
62= 12+c

Which your answer is 50 cause if you take 62 and subtract it to 12 it's 50. So 50 + 12 = 62
5 0
4 years ago
∠QPS is a right angle and m∠QPR = 71°, what is m∠RPS?
natta225 [31]

Answer: <RPS = 161

Step-by-step explanation:

P is the common vertex in all of these angles. From this we know that these have to be adjacent angles (<QPR and <QPS) that equal the whole angle (<RPS)

<QPR+<QPS= <RPS

71+90= 161

(<QPS is a right angle. Right angles are equal to 90 degrees.)

8 0
3 years ago
Can someone plz help plz show work
aliya0001 [1]

Answer:

<h2>LA = 24 ft²</h2>

Step-by-step explanation:

In the base we have the right triangle. Use the Pythagorean theorem for to calculate the hypotenuse:

h^2=4^2+3^2\\\\h^2=16+9\\\\h^=25\to h=\sqrt{25}\\\\h=5\ ft

The Lateral Area is the sum of the areas of three rectangles:

4\ ft\ \times\ 2\ ft\to A_1=(4)(2)=8\ ft^2\\\\3\ ft\ \times\ 2\ ft\to A_2=(3)(2)=6\ ft^2\\\\5\ ft\ \times\ 2\ \ft\to A_3=(5)(2)=10\ ft^2

The Lateral Area:

LA=A_1+A_2+A_3\to LA=8+6+10=24\ ft^2

8 0
3 years ago
EM Company produces two types of laptop computer bags. The regular version requires $32 in capital and 4 hours of labor and sell
expeople1 [14]

Answer:

Step-by-step explanation:

Given that EM company produces two types of laptop computer bags.

Let regular version produced be R and deluxe version be D

Total capital required

= 32R+38D\leq 2100

Total labor hours required

=4R+6D\leq 280

Sales revenue = 46R+55D

Solving the two constraints we have

10D \leq 140

D can be atmost 14 and hence R can be 49

Otherwise if D is made 0, R = 65 maximum

If R is made 0, D maximum is 46

Thus corner points are (65,0) (0.,46) or (49,14)

Sales revenue for (65,0) = 2990

(0,46) is 2530

(49,14) is 3024

Maximum when R =14 and D is 49

5 0
3 years ago
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