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katrin [286]
4 years ago
10

Image: 1 apple, 3 oranges for each of 5 steps on the slider] Explore equivalent ratios by using the slider. Complete the sentenc

es below. The ratio of apples to oranges is 1 to ___. For every __ apples, there are 6 oranges. For every 4 apples, there are ___ oranges. Apples are ___% of the total number of fruits.
Mathematics
2 answers:
siniylev [52]4 years ago
8 0

Answer:

The ratio of apples to oranges is 1 to  

3

.

For every  

2

apples, there are 6 oranges.

For every 4 apples, there are  

12

oranges.

Apples are  

25

% of the total number of fruits.

Step-by-step explanation:

alina1380 [7]4 years ago
4 0
1.5
i hope i helped have a very nice day

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2 years ago
What is DA equal to? Brainiest if correct and please show your answer.
Naddik [55]

Answer:

<h2>DA is equal to <u>25</u> or BA</h2>

Step-by-step explanation:

ABC

ADC

  1. Since we know that line CA is equal to line CA because of <em>reflexive property</em>
  2. Angle BAC and DAC are equal because of <em>definition of an angle bisector</em>
  3. Angle ABC and ADC are equal because of <em>definition of an angle bisector</em>
  4. This will give us <em>ASA</em>, proving to us that all sides and angles are congruent <u>(this was already given to us)</u>
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1 year ago
Convert the polar equation r = 2 secØ to a Cartesian equation.y = 2x = 2x^2 = 2
ss7ja [257]
Polar and cartesian equation<h2>Initial explanation</h2>

Let's analyze the relation between r and x and y:

We have that between the indicated value of r (of the polar coordinates) and x and y (of the cartesian coordinates) there is a relation because they form a triangle. If r changes, then the value of x and y will change.

<h2>STEP 1: given equation</h2>

Using the given equation

r = 2 secØ

we have that

\begin{gathered} r=2secØ \\ \downarrow \\ \frac{r}{2}=secØ \end{gathered}<h2>STEP 2: secØ equation</h2>

Observing the image of the initial explanation we have a right triangle, we know that the equation of

secØ for any right triangle is given by:

\sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}

In this case,

hypotenuse = r

adjacent side = x

then,

\begin{gathered} \sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}=\frac{r}{x} \\ \sec Ø=\frac{r}{x} \end{gathered}<h2>STEP 3: comparison between given equation and secØ equation</h2>

Then, we have that:

\begin{gathered} \sec Ø=\frac{r}{x} \\ \sec Ø=\frac{r}{2} \end{gathered}

This means that:

\begin{gathered} \frac{r}{x}=\sec Ø=\frac{r}{2} \\ \downarrow \\ \frac{r}{x}=\frac{r}{2} \end{gathered}

Then,

x = 2

The equation in cartesian coordinates is x=2.

Answer: x=2

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