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1 year ago

What is DA equal to? Brainiest if correct and please show your answer.

Mathematics

1 answer:

Naddik [55]1 year ago

5 0

Answer:

<h2>DA is equal to 25 or BA</h2>

Step-by-step explanation:

ABC

ADC

Since we know that line CA is equal to line CA because of reflexive property
Angle BAC and DAC are equal because of definition of an angle bisector
Angle ABC and ADC are equal because of definition of an angle bisector
This will give us ASA, proving to us that all sides and angles are congruent (this was already given to us)
So, if BA is 25, and we know that BA is congruent to DA, this tells us that DA is 25

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Find dy/dx by implicit differentiation for ysin(y) = xcos(x)

tatyana61 [14]

Answer:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

Step-by-step explanation:

So we have:

$y\sin(y)=x\cos(x)$

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

$\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]$

Let's do each side individually.

Left Side:

We have:

$\frac{d}{dx}[y\sin(y)]$

We can use the product rule:

$(uv)'=u'v+uv'$

So, our derivative is:

$=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]$

We must implicitly differentiate for y. This gives us:

$=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]$

For the sin(y), we need to use the chain rule:

$u(v(x))'=u'(v(x))\cdot v'(x)$

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

$=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})$

Simplify:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}$

And we are done for the right.

Right Side:

We have:

$\frac{d}{dx}[x\cos(x)]$

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

$=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]$

Differentiate:

$=\cos(x)-x\sin(x)$

So, our entire equation is:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)$

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

$\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)$

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

And we're done!

5 0

2 years ago

Write and evaluate the expression. Then, select the correct answer.

FromTheMoon [43]

zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

4 0

2 years ago

Item 5 Identify the terms, coefficients, and constants in the expression 6 + n x n + 1/2d

Alenkasestr [34]

Answer:

Terms (Variables) = x , d . Their corresponding coefficients = n^2 , 1/2 . Constant = 6

Step-by-step explanation:

6 + n x n + 1/2d

6 + n^2 x + 1/2d

Terms (Variables) = x , d . Their corresponding coefficients = n^2 , 1/2 . Constant = 6

7 0

2 years ago

A sum has five addends. Each addend is a unit fraction. The sum is 1. What are the addends?

Bogdan [553]

I would assume 1/5 is your answer. As 1/5+1/5+1/5+1/5+1/5 = 5/5 which is 1.

4 0

3 years ago

Read 2 more answers

What are the zeros of function g(x)=x2+4x-12

Effectus [21]

Answer:

zeros are -6 and 2

Step-by-step explanation:

let g(x)=0

x²+4x-12=0

x²+6x-2x-12=0

(x+6)(x-2)=0

x+6=0 x-2=0

x= -6 x= 2

5 0

2 years ago