Answer:
The sum of the two numbers is 15
Step-by-step explanation:
Let the counting numbers be x and y.
Then we can write the following equations
x=4y.......1 (one is four times greater )
x(y)=36.....2 (the product of the two)
Putting equation 1 into equation 2, we get
4y(y)=36
Dividing through by 4,we get
Taking square root of both side, we obtain
y=3
Putting the value of y into equation , we get
x=4(3)=12
Hence the numbers are 3 and 12
Therefore the sum of the two numbers is 3+12=15
Answer:
x= 14 hope that helps you out good luck
<h2>
Greetings!</h2>
Answer:
Area is 147.74
Step-by-step explanation:
You need to recall that the equation for the area of a rectangle is:
Length * Width = area
So 16 3/5 * 8 9/10 = area
Rearrange so the whole numbers are being multiplied and the fractions are too:
We need to make the denominator same, this can be done by simply multiplying 3/5 by 2:
3/5 * 2 = 6/10
Now the two numbers can be written as 16.6 and 8.9.
Multiply both numbers by 10:
166 * 89 = 14774
Then divide this by 100 (two lots of division by 10)
14774 ÷ 1000 = 147.74
So the area of the rectangle is 147.74!
<h2>Hope this helps!</h2>
You have the polygon MNOPQR which can be expressed as two rectangles pasted one next to each other.
To see the two rectangles in the picture, you can draw a line parallel to segment MR througn point N.
From the original picture you can state the dimensions of both rectangles.
Call S, the point where the line that you drew intercepts the segment RQ.
Then one rectangle is MNSR and the other rectangle is OPQS.
The measures of the sides of the rectangle MNSR are:
- the length of MN = length of SR = base
- the length of MR = the length of NS.= height
So its area is base * height, which you can all A1.
The measured of the rectangle OPQS are:
- segment OP = segment SQ = segment QR - segment SR = base
- segment PQ = segment OS = height
So its area is base * height, which you can call A2.
Then the area of the polygon MNOPQRS is A1 + A2. One of them is 9 u^2 and the other is what the answer is asking for, and that you have calculated above.
With this procedure you can tell the value needed.
Answer:
<h3>i hope it's helpful for you</h3>
