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emmasim [6.3K]
3 years ago
13

7. As you consider your decision, you think about how most cars lose value over time. If a fully loaded Volkswagen Beetle deprec

iates at a rate of 15%, calculate the value of the car after 10 years if it is currently valued at $30,000. (Car Depreciation Formula: V=I(1−r)t where "V" is the value of the car after "t" years, "I" is the current value, "r" is the rate of depreciation). Round to
Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0
11,949.9126..... by my calculator.
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The median ( Q2 ) divides the data set into two parts, the upper set and the lower set. The lower quartile ( Q1 ) is the median of the lower half, and the upper quartile ( Q3 ) is the median of the upper half. Example: Find Q1 , Q2 , and Q3 for the following data set, and draw a box-and-whisker plot.
6 0
3 years ago
What is the following sum in simplest form √8 + 3√2 + √32
boyakko [2]
C.
√8+3√2+√32=2√2+3√2+4√2=9√2
7 0
3 years ago
Expand and simplify (x-2)(x-1)
mr_godi [17]

Answer:

(x - 3) x + 2

Step-by-step explanation:

1/4 (2 x - 3)^2 - 1/4

5 0
2 years ago
I really need help with this please help best aswer gets brainliest
svet-max [94.6K]

Answer:

Relative frequency is 7.41% or 0.0741

Step-by-step explanation:

Given

The Attached Table

Required

Calculate the relative frequency of the class with lower limit 27

Relative Frequency is calculated by dividing individual frequency by the total frequency

Mathematically,

Relative\ Frequency = \frac{Individual\ Frequency}{Total\ Frequency}

The total frequency of the given data is 6+8+4+2+5+2

Total\ Frequency = 27

The class with lower limit 27 has a frequency of 2;

Hence;

Relative\ Frequency = \frac{Individual\ Frequency}{Total\ Frequency} becomes

Relative\ Frequency = \frac{2}{27}

Relative\ Frequency = 0.07407407407

Relative\ Frequency = 0.0741 (Approximated)

You may also leave your answer in percentage form

Relative\ Frequency = 0.0741 * 100\%

Relative\ Frequency = 7.41 \%

Hence, the relative frequency is 7.41% or 0.0741

7 0
3 years ago
Read 2 more answers
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
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