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Zinaida [17]
2 years ago
14

Two paths each 2m wide run across the middle of a rectangular field. If the area of the cross path is 196m and its length is 60m

, find its breadth​
Mathematics
1 answer:
Naddik [55]2 years ago
5 0

Answer:

d=2m

Area(A)=196m

l=60m

Now,

A=d(l+b-d)

196=2(60+b-2)

196=2(58+b)

196=116+2b

2b=196-116

2b=80

b=40m

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juin [17]

Answer:

8 (see work)

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Step-by-step explanation:

There's attached work for explanation

8 0
3 years ago
Please help me on this question
Delicious77 [7]

Answer:

√20

Or

2√5

Step-by-step explanation:

It is very easy just substitute

It will be:

3 0
3 years ago
Oof this is probably really simple to most of y'all but I'm out of it.
Lelechka [254]

Answers:

  • angle1 = 156 degrees
  • angle2 = 24 degrees

=======================================================

Explanation:

The two angles form a straight line, which is 180 degrees

Add up the angle expressions and set the sum equal to 180.

(angle1) + (angle2) = 180

(4x) + (x-15) = 180

(4x+x)-15 = 180

5x-15 = 180

5x = 180+15

5x = 195

x = 195/5

x = 39

We use that x value to find each missing angle

  • angle1 = 4x = 4*39 = 156 degrees
  • angle2 = x-15 = 39-15 = 24 degrees

Then notice how angle1+angle2 = 156+24 = 180 to verify the answer.

Side note: Angles that add to 180 are considered supplementary.

6 0
2 years ago
(1) Tom took a trip of 1,020 miles. He traveled by train at 55 miles an hour and the same number of hours by plane at 285 mph.
Maurinko [17]
<h3>Answer:</h3>

B) 6 hours

<h3>Step-by-step explanation:</h3>

Let h represent the total trip time. Then h/2 is the time spent traveling at each speed. The distance covered is ...

... distance = speed · time

The sum of the distances in each mode is the total distance.

... 1020 = 55·h/2 +285·h/2

... 2040 = h·(55+285) . . . . multiply by 2

... 2040/340 = h = 6 . . . . . . . divide by the coefficient of h

The trip took a total of 6 hours.

4 0
3 years ago
John often speed while driving to school in order to arrive on time. The probability that he will speed to school is 0.75. If th
BartSMP [9]

Answer:

0.33

Step-by-step explanation:

Given the following :

P(speeding) = p(s) = 0.75

P(being stopped) = p(t)

P(speeding and gets stopped) = p(s n t) = 0.25

Find the probability that he is stopped, given that he is speeding is written as P(t | s) ;

P(t | s) = p(s n t) / p(s)

P(s n t) = 0.25

P(s) = 0.75

Hence,

P(t | s) = 0.25 / 0.75

P(t | s) = 0.33

3 0
3 years ago
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