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amid [387]
3 years ago
13

O is the center of the circle. Assume that lines that appear to be tangent are tangent. What is the value of x?

Mathematics
1 answer:
Anna [14]3 years ago
4 0

Answer:

56

Step-by-step explanation:

We know that radius of a circle is perpendicular to the tangent of the circle at the point of contact.

\therefore x\degree +90\degree +90\degree+124\degree =360\degree\\\therefore x\degree +304\degree =360\degree\\\therefore x\degree =360\degree-304\degree\\\huge\purple{\boxed{\therefore x\degree =56\degree}}

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Someone plz help me
topjm [15]

x = 375 and y = 6300. Option C.

Step-by-step explanation:

From the given data we need to find the value of x and y.

First, we will find out the ratio of area and the force.

\frac{Area}{Force}  = \frac{125}{1875} =\frac{150}{2250} =\frac{175}{2625} = \frac{1}{15}

So,

\frac{x}{5625} = \frac{1}{15}

or, x = \frac{5625}{15} = 375

Again,

\frac{420}{y} = \frac{1}{15}

or, y = 420×15 = 6300

Hence,

x = 375 and y = 6300.

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3 years ago
Cardinal Corporation, a calendar year taxpayer, receives dividend income of $250,000 from a corporation in which it holds a 10%
Nitella [24]
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3 years ago
An online company wants to establish ratings for the products they provide. To do so, they ask visitors to their website to eval
Lemur [1.5K]

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Step-by-step explanation:

8 0
3 years ago
2.) AN *
WINSTONCH [101]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
A certain car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year
icang [17]

Answer:

b(b/a)^2

Step-by-step explanation:

Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then

b = a - (p% × a) = a(1-p%)

b/a = 1 - p%

p% = 1 - b/a = (a-b)/a

Let the worth of the car on December 31, 2012 be c

then

c = b - (b × p%) = b(1-p%)

Let the worth of the car on December 31, 2013 be d

then

d = c - (c × p%)

d = c(1-p%)

d = b(1-p%)(1-p%)

d = b(1-p%)^2

d = b(1- (a-b)/a)^2

d = b((a-a+b)/a)^2

d = b(b/a)^2 = b^3/a^2

The car's worth on December 31, 2013 =  b(b/a)^2 = b^3/a^2

4 0
3 years ago
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