Alright here goes, it’s 7.05024•10^11
Explination:
Maths…
Hope this helps!
Let's do this by Briot-Ruffini
First: Find the monomial root
x - 2 = 0
x = 2
Second: Allign this root with all the other coeficients from equation
Equation = -3x³ - 2x² - x - 2
Coeficients = -3, -2, -1, -2
2 | -3 -2 -1 -2
Copy the first coeficient
2 | -3 -2 -1 -2
-3
Multiply him by the root and sum with the next coeficient
2.(-3) = -6
-6 + (-2) = -8
2 | -3 -2 -1 -2
-3 -8
Do the same
2.(-8) = -16
-16 + (-1) = -17
2 | -3 -2 -1 -2
-3 -8 -17
The same,
2.(-17) = -34
-34 + (-2) = -36
2 | -3 -2 -1 -2
-3 -8 -17 -36
Now you just need to put the "x" after all these numbers with one exponent less, see
2 | -3x³ - 2x² - 1x - 2
-3x² - 8x - 17 -36
You may be asking what exponent -36 should be, and I say:
None or the monomial. He's like the rest of this division, so you can say:
(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:
(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)
Just divide the rest by the monomial.
Answer:
This means that the correct initial value problem for the population p(t) as a function of time is is ![P(0) = 1000](https://tex.z-dn.net/?f=P%280%29%20%3D%201000)
Step-by-step explanation:
The population of a town increases at a rate proportional to its population:
This means that this situation is modeled by the following differential equation:
![\frac{dP}{dt} = kP](https://tex.z-dn.net/?f=%5Cfrac%7BdP%7D%7Bdt%7D%20%3D%20kP)
In which k is the growth rate.
By separation of variables, the solution is given by:
![P(t) = P(0)e^{kt}](https://tex.z-dn.net/?f=P%28t%29%20%3D%20P%280%29e%5E%7Bkt%7D)
In which P(0) is the initial population.
Initial population of 1000.
This means that the correct initial value problem for the population p(t) as a function of time is is ![P(0) = 1000](https://tex.z-dn.net/?f=P%280%29%20%3D%201000)
Answer:
x + 3
Step-by-step explanation:
if x represents a number then 3 more than the number means addition of 3 to the number ( x )
so, required phrase is ;
=》x + 3