Answer:
y = x^2 + 9x + 6 No remainder.
Step-by-step explanation:
The divisor will be 3 The sign on the divisor switches.
3 || 1 + 6 - 21 - 18 ||
3 27 + 18
================================
1 9 6 0
The answser is x^2 + 9x + 6
1. (5x-8)=(8x-17)
5x-8x=-17+8
-3x=-9
x=3
2. (3x+5) + (4x-7) =180
3x+5+4x-7=180
3x+4x=180-5+7
7x=182
x=26
Answer:
The answer is 
Step-by-step explanation:
The expression is
![\frac{7\pi }{12}^{c}\\= \frac{7\pi }{12}*\frac{180}{\pi }^{0} \,;[1^{c}=\frac{180}{\pi}^{0}]\\=7*15\\=105^{0}](https://tex.z-dn.net/?f=%5Cfrac%7B7%5Cpi%20%7D%7B12%7D%5E%7Bc%7D%5C%5C%3D%20%5Cfrac%7B7%5Cpi%20%7D%7B12%7D%2A%5Cfrac%7B180%7D%7B%5Cpi%20%7D%5E%7B0%7D%20%5C%2C%3B%5B1%5E%7Bc%7D%3D%5Cfrac%7B180%7D%7B%5Cpi%7D%5E%7B0%7D%5D%5C%5C%3D7%2A15%5C%5C%3D105%5E%7B0%7D)
Hope you have understood this....
pls mark my answer as the brainliest
Hello!
Here are some rules to determine the number of significant figures.
- Numbers that are not zero are significant (45 - all are sigfigs)
- Zeros between non-zero digits are significant (3006 → all are sigfigs)
- Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
- Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
- Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
- In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)
Now, let's find the number of significant figures in each given number.
A). 296.54
Since these digits are all <em>non-zero</em>, there are 5 significant figures.
B). 5003.1
Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.
C). 360.01
Again, the two zeros are between non-zero digits. There are 5 significant figures.
D). 18.3
All of these digits are non-zero, hence, there are 3 significant figures.
Therefore, expression D has the fewest number of significant figures being 3.
Two less than 5 times a number is 9
