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Daniel [21]
4 years ago
13

Please Help....................................

Mathematics
1 answer:
vazorg [7]4 years ago
5 0
The answer are:
(-4,5)

(2,2)
 
(-1, -3)

(3,4)

(2,-1)

(-5,6)
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Please help! Im so stuck on this and cant figure it out
Reptile [31]
First, we split the figure into two shapes, a triangle and a trapezoid. First, we know that the length of the base of the right triangle is 2, because in a 30-60-90 triangle, the side next to the 60° is half of the hypotenuse. Then, the length of the height would be 2 times root 3, which is 3.46410161514. Height is 3.46410161514 meters and base is 2 meters. We multiply the base times the height, and we get 6.92820323028 meters squared. This is the area of the triangle. Since we know that the base of the triangle is 2, we can do 5-2 to find the first base of the trapezoid, which is 3. We know that the height is 3.46410161514, the first base is 3, and that the second base is 5, so we plug it into our equation which is base1 + base2 over 2 times the height. We plug it in and get approximately 13.85641. Then we round to the tenths place, and we get 13.86 meters squared of the figure. Brainliest?
5 0
3 years ago
a 14 ounce energy drink contains 10 1/2 teaspoons of sugar. How much sugar is in one ounce of the drink?
Y_Kistochka [10]
In this case u need to divide 10 1/2 by 14 coz theres 14 ones in 14
so 10 1/2 divided by 14 = 0.75
<em>so theres 0.75 sugar in one ounce of drink ;)</em>
5 0
4 years ago
What is the equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)2 + 4?
son4ous [18]
 <span>What is the equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)2 + 4?


</span>A. x=3/2
8 0
4 years ago
Read 2 more answers
How many different four-letter arrangements can be formed using the six letters A, B, C, D, E and F, if the first letter must be
Ainat [17]

Answer with Step-by-step explanation:

We are given that A,B,C,D,E and F.

We have to find the number of  different four -letter arrangements can be formed using given six letters a,if the first letter must be C and one of the other letters must be B and no letter can be used more than once in the arrangement.

Number of letters=6

We have to arrange  four letter  out of six

After fixing C and B then we choose only two letters out of remaining four letters and repetition is not allowed.

Permutation formula :nP_r=\frac{n!}{(n-r)!}

We have n=4 an r=2

Using this formula and substitute the values

Then, we get 4P_2=\frac{4!}{(4-2)!}=\frac{4\times 3\times 2!}{2!}

4P_2=4\times 3=12

Hence, number of different four -letter arrangements can be formed using six letters when repetition is not allowed=12

8 0
4 years ago
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NEED HELP ASAP WITHIN 10 MINUETS MY ASSIGNMENT IS DO PLEASE HELP!
Anna [14]

Answer: I do not have expertise on this so I won't answer the exact problem but this sounds like exponential decay, where you have the decay rate. I know that the formula for exponential decay is: y = a(1 - r)^x

I'm sorry if this does not help much I don't have expertise on this. Sorry again.

Step-by-step explanation:

5 0
4 years ago
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