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Oksi-84 [34.3K]
2 years ago
7

On Sunday, a local hamburger shop sold a combined total of 378 hamburgers and cheeseburgers. The number of cheeseburgers was sol

d 2 times the number of hamburgers. How many hamburgers were sold?
Mathematics
1 answer:
ipn [44]2 years ago
5 0

Answer:

The number of hamburgers sold was 126.

Step-by-step explanation:

Let h = number of hamburgers sold

let c = cheeseburgers sold

c+h = 378

c = 2h

Substitute c =2h into c+h =278

c+h =378

2h+h = 378

Combine like terms

3h = 378

Divide by 3

3h/3 =378/3

h =126

The number of hamburgers sold was 126.

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Answer:

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<h2>2 \sqrt{2 }  \:  \: or \:  \: 2.828 \:  \:  \: units</h2>

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<h3>d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\</h3>

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From the question the points are

E(-3,4) and B(-1,6)

The distance between them is

<h3>|EB|  =  \sqrt{ ({ - 3 + 1})^{2} +  ({4 - 6})^{2}  }  \\  =  \sqrt{ ({ - 2})^{2}  +  ({ - 2})^{2} }  \\  =  \sqrt{4 + 4}  \ \   \\  = \sqrt{8}</h3>

We have the final answer as

<h3>2 \sqrt{2 }  \:  \: or \:  \: 2.828 \:  \:  \: units</h3>

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