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tamaranim1 [39]
3 years ago
6

In 448,244, how is the relationship between the first pair of 4's the same as the relationship between the second pair of 4's?

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0
They are all whole numbers , Judy in different spaces and positions
You might be interested in
List least to greatest
max2010maxim [7]

Answer:

C, 3 1/2, 3 19/20, 3 39/40

Step-by-step explanation:

to make this a bit easier, we can put the mixed numbers into improper fractions:

3 39/40 becomes 159/40

3 19/20 becomes 79/20

3 1/2 becomes 7/2

comparing them to each other, we see they have unlike denominators. we need to get the denominators alike so we can compare them easier

the fractions all have a common denominator of 40, so we need to multiply each fraction by a number that gives us a denominator of 40

159/40 is already fine

79/20 needs to be multiplied by 2 to get a denominator of 40

79/20 x 2 = 158/40

7/2 needs to be multiplied by 20 to get a denominator of 40

7/2 x 20 = 140/40

from least to greatest, we have the following:

140/40, 158/40, 159/40

in their original form this would be:

3 1/2, 3 19/20, 3 39/40

the answer would be C

4 0
3 years ago
Can someone help me with this math work my brain broke-
marta [7]

Answer:

1. 90

2.60

3.30

4. 40

5. 80

6. 60

7. 30

8. 30

9. 120

Total for all triangles=180

Step-by-step explanation:

In all the problems, you have to solve for y.  This can be done because the three angles are supplementary  For example, in the first diagram, you have:

3y+2y+y=180

6y=180

y=30

It's fairly easy to solve from there.  Just more multiplying and subtracting.

8 0
2 years ago
What is the area of the base. explain, please :)
Ber [7]

Answer:

4,200

Step-by-step explanation:

7 0
3 years ago
If f(x) = 3x – 12, what is f(2)?
fredd [130]
It would be B. -6.

f(x) = 3x-12
f(2) = 3(2)-12
f(2) = 6-12
f(2) = -6
5 0
3 years ago
Read 2 more answers
Help me with 2 please
GarryVolchara [31]
The answer to your question would be C 6 can be put into 18 and 24
7 0
3 years ago
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