Answer:
B) perpendicular
Step-by-step explanation:
i graphed them
This is in slope-intercept form, so you can think of it as being y=mx+b. Invert m (the slope) and flip its sign, and then substitute the x and y values in and solve for b. The answer is y=7/2x-20.
<h2>Hello!</h2>
The answer is:
C. Cosine is negative in Quadrant III
<h2>
Why?</h2>
Let's discard each given option in order to find the correct:
A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).
B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.
C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.
D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)
Have a nice day!
Answer:
You can find the point of intersection of the line with the y-axis and the the point of intersection of the line with the x-axis. See the graph attached.
Step-by-step explanation:
Find the intersection with the y-axis. Substitute 
into the equation and solve for y:
≈3.33
Find the intersection with the x-axis. Substitute 
into the equation and solve for x:
Now, you know that the line passes through the point (0,3.33) and (-10,0). Now you can graph the function. (Observe the graph attached)
