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3 years ago

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Ahmed and Gavin are playing both chess and checkers. The probability of Ahmed winning the chess game is 45\%45%45, percent. The

probability of Ahmed winning the checkers game is 0.360.360, point, 36. Which of these events is more likely? Choose 1 answer: Choose 1 answer: (Choice A) A Ahmed wins the chess game. (Choice B) B Ahmed wins the checkers game. (Choice C) C Neither. Both events are equally likely.

1 answer:

Brilliant_brown [7]3 years ago

7 0

Answer: A - Ahmed wins the chess game

Step-by-step explanation:

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Suppose a square ABCD has a side length of 1 unit. The arcs BD and AC are circular arcs with centers at A and D, respectively. F

Likurg_2 [28]

Answer:

$1-\frac{\sqrt{3} }{4}-\frac{\pi}{6}$

Step-by-step explanation:

The missing figure is shown in the attachment

The area of the shaded region = Area of Square - (Area of sector AOB + Area of equilateral triangle BOC + Area of sector COD)

Area of Sector AOB=Area of Sector COD= $\frac{30}{360}*\pi*1^2=\frac{\pi}{12}$

Area of equilateral triangle = $\frac{1}{2}*r*\frac{\sqrt{3} }{2}*r= \frac{1}{2}*1*\frac{\sqrt{3} }{2}*=\frac{\sqrt{3} }{4}$

Area of shade region = $1^2-\frac{\sqrt{3} }{4}-\frac{\pi}{12}*2$

$1-\frac{\sqrt{3} }{4}-\frac{\pi}{6}$

6 0

3 years ago

Jessica is a custodian at Oracle Arena. She waxes 20 \text{ m}^220 m 2 20, space, m, start superscript, 2, end superscript of th

Evgesh-ka [11]

Given that Jessica is a custodian at Oracle Arena.

She waxes 20 square meters space of the floor in 5/3 of an hour. Jessica waxes the floor at a constant rate means rate will remain fixed for any hour.

Now we have to find about how many square meters can she wax per hour.

To find that we just need to divide 20 squaer meters by 5/3 hours

$\frac{20}{\left(\frac{5}{3}\right)}$

$=20\cdot\frac{3}{5}$

$=\frac{60}{5}$

=12

Hence final answer is 12 square meters can she wax per hour.

Which can also be written as $12m^2$ per hour.

4 0

3 years ago

Read 2 more answers

A billboard designer has decided that a sign should have 3 ft margins at the top and bottom and 5 ft margins on the left and rig

elixir [45]

Answer:

The width of billboard is "[x]" and the height of billboard is "[y"]. If total area of billboard is $9000 ft^2$ then $9000=xy$

Step-by-step explanation:

• The total width of billboard is [x]. Therefore the width of printed area will be (x-10) by excluding margin of left and right side.

• The total height of billboard is [y]. Therefore the height of printed area will be [(y-6)] by excluding the margin of top and bottom from the total height.

• To find the printed area of billboard calculations are given below:

$& 9000=xy$

$& y=\frac{9000}{x} \\ & A=(x-10)(y-6) \\ & A=xy-6x-10y+60 \\ & A=x\left( \frac{9000}{x} \right)-6x-10\left( \frac{9000}{x} \right)+60 \\ & A=9060-6x-\frac{9000}{x} \\$

On taking the first order derivative of A

$A'=-6+\left( \frac{90000}{{{x}^{2}}} \right)$

$& \left( \frac{90000}{{{x}^{2}}} \right)-6=0 \\ & 6{{x}^{2}}=90000 \\ & x=\sqrt{15000} \\ & y=\frac{9000}{x}=\frac{90000}{\sqrt{15000}}=10\sqrt{150} \\$

• Hence $x=10\sqrt{150}$ and $y=\frac{900}{\sqrt{150}}$

Learn More about Differentiation Here:

brainly.com/question/13012860

7 0

3 years ago

Read 2 more answers

Answer please and explain

raketka [301]

The rise is 2 and the run is 3

8 0

3 years ago

ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

7 0

3 years ago