The roots of the quadratic equation 3y² + 3(4y² - 2) is ± √(1/7).
<h3>What is a quadratic equaton?</h3>
A quadratic equation is an algebraic expression in the form of variables and constants.
A quadratic equation has two roots as its degree is two.
Given, 3y² + 3(4y² - 2).
3y² + 12y² - 2.
14y² - 2.
Let 14y² - 2 = 0.
14y² = 2.
y² = (2/14).
y = ± √(2/14) Or ± √(2/2×7) Or ± √(1/7).
learn more about quadratic equations here :
brainly.com/question/17177510
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