Answer:
1) 3 bags of candy, 5 picture frames and 1 pack of stickers
2) Both option B and C should be eliminated
Step-by-step explanation:
Now according to the data given, total number of items bought is
x + y + z = 9 . . . (A)
Since, total cost is $16, and we know the unit cost of each item
so for x, total cost is number of items multiply by unit price
Total cost for x = (1) x (x)
for y, total cost is number of items multiply by unit price
Total cost for y = (2) x (y)
for z, total cost is number of items multiply by unit price
Total cost for z = (3) x (x)
So equation for total cost is
x + 2y + 3z = 16 . . .(B)
As we know by the data given that bags of candy are three times as compared to stickers
So, x = 3z
putting value of x in equation (A)
3z + y + z = 9
4z + y = 9 or y = 9 - 4z
Putting value of x and y in terms of z in equation B, we get
3z + 2(9 - 4z) + 3z = 16
6z + 18 - 8z = 16
-2z = -2
z = 1
Now x = 3z, so x = 3
and also y = 9 - 4z, so y = 5
so Taylor purchased
3 bags of candy, 5 picture frames and 1 pack of stickers
Now for the equations given below
A is valid because question tells that Taylor bough 3 bags of candy as compared to one pack of stickers and since total number of items purchased is equal to 9, so D is also right.
It might be possible that in options B and C it is typo error, but both donot fulfill the situation given in the question.