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sladkih [1.3K]
3 years ago
6

Sammy Sales had the following receipts for his tree trimming business for the first six months of the year. What is the average

of his sales for this period? (Use a thousands comma where applicable.) Jan. Feb. Mar. Apr. May Jun. $1,205 $1,450 $1,530 $1,655 $1,610 $1,710 $
Mathematics
1 answer:
fredd [130]3 years ago
6 0

average =  \frac{sum \:  \: of \:  \:all \:  \:  obeservations}{no. \:  \: of \: observaions}

=  \frac{1205 + 1450 + 1530 + 1655 + 1610 + 1710}{6}

=  \frac{9160}{6}

=  1526.66

___________________________________________

1526.66 is the average of his sales for this period.

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A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Minchanka [31]
<h2><u>Answer with explanation</u>:</h2>

Let \mu be the distance traveled by deluxe tire .

As per given , we have

Null hypothesis : H_0 : \mu \geq50000

Alternative hypothesis : H_a : \mu

Since H_a is left-tailed and population standard deviation is known, thus we should perform left-tailed z-test.

Test statistic : z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overline{x}= sample mean

\mu= Population mean

s=sample standard deviation

For n= 31,\ \sigma=8000,\ \overline{x}=46,800\ \&\ s=46,800, we have

z=\dfrac{46800-50000}{\dfrac{8000}{\sqrt{31}}}=-2.23

By using z-value table,

P-value for left tailed test : P(z≤-2.23)=1-P(z<2.23)   [∵P(Z≤-z)=1-P(Z≤z)]

=1-0.9871=0.0129

 Decision : Since p value (0.0129) < significance level  (0.05), so we reject the null hypothesis .

[We reject the null hypothesis when p-value is less than the significance level .]

Conclusion : We do not have enough evidence at 0.05 significance level to support the claim that t its deluxe tire averages at least 50,000 miles before it needs to be replaced.

4 0
3 years ago
How do you solve 12x =144
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1st. Try to make x by itself. Divide 12 on each side.
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8 0
3 years ago
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What is the simplified form of x+5/3x+4 + x+4/x+3
alina1380 [7]

x +  \frac{5}{3}x + 4 + x +  \frac{4}{x} + 3 \\ x +  \frac{5x}{3}+ 4 + x +  \frac{4}{x}+ 3 \\ (x +  \frac{5x}{3}  + x) + (4 + 3) +  \frac{4}{x}  \\ x =  \frac{11x}{3}  + 7 +  \frac{4}{x}

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3 years ago
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Answer:

The last one

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4 0
3 years ago
Millimeters<br> Equal 15 centimeters 4 millimeters
Svetradugi [14.3K]

154mm

we know that  1cm = 10 mm

 therefore      15cm= 10*15 mm

                               =  150 mm

and 4 mm

we get total mm= 15cm +4mm

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