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musickatia [10]
3 years ago
10

Find the equation of the line. Use exact numbers. y= ? x+ ?

Mathematics
2 answers:
OLga [1]3 years ago
7 0
The answer will be:
y=3x+3. Hope it help!
devlian [24]3 years ago
4 0
The answer is y=3x+3
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PLS HELP BRAINLIEST
laiz [17]

Answer:

a) AB = 17 m

b) AC = 20.8 m

Step-by-step explanation:

Pythagorean theorem

a^2 + b^2 = c^2

a)

AB^2 = (26-11)^2 + 8^2

AB^2 = 15^2 + 8^2

AB^2 =  225 + 64

AB^2 = 289

AB = 17 m

b)

AC^2 = AB^2 + BC^2

AC^2 = 17^2 + 12^2

AC^2 =289 + 144

AC^2 = 433

AC = 20.8 m

7 0
3 years ago
5x^2 + 19x + 12=0<br> how do i figure this out
zlopas [31]

Answer:

x=−4/5 or x=−3

Step-by-step explanation:

Step 1: Factor left side of equation.

(5x+4)(x+3)=0

Step 2: Set factors equal to 0.

5x+4=0 or x+3=0

x=−4/5 or x=−3

3 0
3 years ago
Help me with this question, please!! I don't understand!!
Gwar [14]

Answer:

Presentation on theme: "Geometry Spheres CONFIDENTIAL."— Presentation transcript:

Step-by-step explanation:

Search this up and watch the video it may explain it to you better. I hope this helps!

6 0
3 years ago
What is 33/7 as a mixed number
melamori03 [73]
33/7 is an improper fraction. 

To make it a mixed fraction, do this:-

How many times does 7 go into 33?

About 4 times.

4*7 = 28

4 is our whole number.

Now, subtract to get the numerator. 

33-28 = 5

4    5/7

Final answer:  4  5/7
5 0
3 years ago
Read 2 more answers
Consider a melody to be 7 notes from a single piano octave, where 2 of the notes are white key notes and 5 are black key notes.
igor_vitrenko [27]

Answer:

35,829,630 melodies

Step-by-step explanation:

There are 12 half-steps in an octave and therefore 12^7 arrangements of 7 notes if there were no stipulations.

Using complimentary counting, subtract the inadmissible arrangements from 12^7 to get the number of admissible arrangements.

\displaystyle \_\_ \:B_1\_\_ \:B_2\_\_ \:B_3\_\_ \:B_4\_\_ \:B_5\_\_

B_1 can be any note, giving us 12 options. Whatever note we choose, B_2, B_{...} must match it, yielding 12\cdot 1\cdot 1\cdot 1\cdot 1=12. For the remaining two white key notes, W_1 and W_2, we have 11 options for each (they can be anything but the note we chose for the black keys).

There are three possible arrangements of white key groups and black key groups that are inadmissible:

WWBBBBB\\WBBBBBW\\BBBBBWW

White key notes can be different, so a distinct arrangement of them will be considered a distinct melody. With 11 notes to choose from per white key, the number of ways to inadmissibly arrange the white keys is \displaystyle\frac{11\cdot 11}{2!}.

Therefore, the number of admissible arrangements is:

\displaystyle 12^7-3\left(\frac{12\cdot 11\cdot 11}{2!}\right)=\boxed{35,829,630}

6 0
2 years ago
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