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kolezko [41]
3 years ago
6

How do I find the slope of the line through (–9, –10) and (–2, –5)?

Mathematics
2 answers:
otez555 [7]3 years ago
8 0
Finding a slope in a number line is easy just  
Steps:
Identify two points on the line
Select one to be (x 1, y 1) and the other to be (x 2, y 2)
Use the slope the slope equation to calculate slope.
Thank you 
storchak [24]3 years ago
4 0
Answer:
slope of line is 5/7

Explanation:
The slope of the line can be calculated using the following rule:
slope = \frac{y2-y1}{x2-x1}

The given points are:
(-9,-10) which represent (x1,y1)
(-2,-5) which represent (x2,y2)

Substitute with the points in the above equation to get the slope as follows:
slope = \frac{-5-(-10)}{-2-(-9)} = 5/7

Hope this helps :)

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Subtract fractions like 42/7- 2 1/5
dangina [55]

Answer:

3.8 in decimal form, or 3 4/5

Step-by-step explanation:

I just used a calculator, sorry :(

anyways, hope this helped! :)

6 0
2 years ago
Solve the puzzle
wolverine [178]

Answer:

95891769

Step-by-step explanation:

This is extract from a brain teaser exercise in which sequence is formed to identify the numbers. In this brain teaser we have made combinations of different numbers which lead to the correct answer. The two correct forms of number are given which are used as a base for determining the correct answer.

4 0
2 years ago
Factor out the greatest common factor<br> 15x^2-21x<br> ^=exponent
gavmur [86]

Answer:

3x

Step-by-step explanation:

3x(5x-7)

brainliest!

4 0
2 years ago
What is the value of x in the equation 5x+3 - 4x?
Dafna1 [17]

5x + 3 - 4x = 0

x + 3 = 0

x = -3

Hope this helps :)

6 0
3 years ago
Find the derivative of f(x) = 2x^2 - 4x +3
ivolga24 [154]

Explanation

2x^2-4x+3

When taking derivatives of polynomials, we primarily make use of the power rule.

Power rule.

\begin{gathered} f(x)=x^n \\ \text{then} \\ f^{\prime}(x)=nx^{n-1} \end{gathered}

also, the derivate of a sum is the sum of the derivates

hence

\begin{gathered} g(x)=f(x)+h(x)+\ldots z(x) \\ g^{\prime}(x)=f^{\prime}(x)+h^{\prime}(x)+\ldots.z^{\prime}(x) \end{gathered}

Step 1

apply:

\begin{gathered} f(x)=2x^2-4x+3 \\ f^{\prime}(x)=2\cdot2x^{2-1}-4(1)x^{1-1}+ \\ f^{\prime}(x)=4x^{}-4(1)x^0+3^0 \\ f^{\prime}(x)=4x^{}-4(1)(1) \\ f^{\prime}(x)=4z-4 \end{gathered}

therefore, the answer is

8 0
1 year ago
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