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kolezko [41]
3 years ago
6

How do I find the slope of the line through (–9, –10) and (–2, –5)?

Mathematics
2 answers:
otez555 [7]3 years ago
8 0
Finding a slope in a number line is easy just  
Steps:
Identify two points on the line
Select one to be (x 1, y 1) and the other to be (x 2, y 2)
Use the slope the slope equation to calculate slope.
Thank you 
storchak [24]3 years ago
4 0
Answer:
slope of line is 5/7

Explanation:
The slope of the line can be calculated using the following rule:
slope = \frac{y2-y1}{x2-x1}

The given points are:
(-9,-10) which represent (x1,y1)
(-2,-5) which represent (x2,y2)

Substitute with the points in the above equation to get the slope as follows:
slope = \frac{-5-(-10)}{-2-(-9)} = 5/7

Hope this helps :)

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Pi I want pi pls help with pi
timurjin [86]

Answer:

pi is 3.14

Step-by-step explanation:

3 0
2 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
2 years ago
PLEASE HURRY!!!
Mashutka [201]

Answer:

C

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
What are the values of a and b?
ivann1987 [24]

Answer:

<h2>a = 400/21, b = 580/21</h2>

Step-by-step explanation:

Small triangles are similar. Therefore, the sides are proportional

\dfrac{a}{20}=\dfrac{20}{21}               <em>cross multiply</em>

21a=(20)(20)       <em>divide both sides by 21</em>

a=\dfrac{400}{21}

For b, we can use the Pythagorean theorem:

b^2=\left(\dfrac{400}{21}\right)^2+20^2\\\\b^2=\dfrac{160000}{441}+400\\\\b^2=\dfrac{160000}{441}+\dfrac{176400}{441}\\\\b^2=\dfrac{336400}{441}\to b=\sqrt{\dfrac{336400}{441}}\\\\b=\dfrac{\sqrt{336400}}{\sqrt{441}}\\\\b=\dfrac{580}{21}

3 0
3 years ago
Plzzz helpppppp!!!!!!
Tema [17]

Answer:

(c) h(3) = 1

Step-by-step explanation:

Given

The attached graph

Required

Find h(3)

The formula to use in solving this is:

y = h(x)

Substitute 3 for x

y = h(3)

From the attached graph, the value od x = 3 points to the value of y = 1.

So, we have:

y = 1

5 0
2 years ago
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