Hyperbola centered at the origin, vertex (0,19), asymptote y = (19/16) x
The axis is the y axis so this hyperbola has the form

We have (0,19) on the hyperbola so a=19. I'm going to take a wild guess that b=16 so our hyperbola has equation:

How do we find the asymptote? I don't remember, it's going to be approximately the line from the origin to some point with really big x and y.

As x gets big the +1 will matter less and less, so the asymptote is




Our guess was right!
Answer: 
Answer:
The answer is google
Step-by-step explanation:
G:d
O:r
O:u
G:g
L:s
E:
4 a. 2/5 (I picked a random number that fits in the blank)
b. √40
i hope this helps :)
Answer:
yes in some cases
Step-by-step explanation:
Answer:
5 goes into 1 1/5 times.
1 ÷ 5 = 1/5
"Going into" something is like saying divided by backwards